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Figure 6 shows a diagram of the Michelson-Morley interferometer that was used to try to detect the absolute motion of the Earth through the ether (either) - AQA - A-Level Physics - Question 4 - 2018 - Paper 7

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Figure 6 shows a diagram of the Michelson-Morley interferometer that was used to try to detect the absolute motion of the Earth through the ether (either). Light fr... show full transcript

Worked Solution & Example Answer:Figure 6 shows a diagram of the Michelson-Morley interferometer that was used to try to detect the absolute motion of the Earth through the ether (either) - AQA - A-Level Physics - Question 4 - 2018 - Paper 7

Step 1

Explain how the experiment provided a means of testing the idea that the Earth had an absolute motion relative to the ether.

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Answer

The Michelson-Morley experiment was designed to detect the presence of the ether by observing interference patterns created by light traveling down two different paths. A shift in the fringe pattern was predicted due to the motion of the Earth through the ether, which would result in a difference in the time taken for light to travel along each path.

When the apparatus was rotated by 90°, the paths exchanged their roles. If the Earth were moving through the ether, a noticeable shift in the interference pattern would occur, reflecting a change in light travel times. However, the actual experiment found no significant shift, thereby contradicting the ether theory.

This outcome led to the conclusion that the Earth does not have an absolute motion through the ether, supporting the idea that the laws of physics are the same in all inertial frames.

Step 2

State this postulate.

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Answer

The invariance of the speed of light in free space/vacuum.

Step 3

State the other postulate of Einstein’s theory of special relativity.

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Answer

Laws of physics have the same form in all inertial frames.

Step 4

Determine the percentage of muons that reach the detector.

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Answer

To calculate the time of flight for a muon traveling at 0.99c, we first find the time taken:

extTime=1310extm0.99c ext{Time} = \frac{1310 ext{ m}}{0.99 c}

Using the speed of light, c3×108 m/sc \approx 3 \times 10^8 \text{ m/s}, we find:

t=13100.99×3×1084.41×106 st = \frac{1310}{0.99 \times 3 \times 10^8} \approx 4.41 \times 10^{-6} \text{ s}

Looking at the graph for the percentage remaining, we find that for a time of approximately 4.41×106 s4.41 \times 10^{-6} \text{ s}, the percentage of muons remaining is approximately 68%.

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