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Question 2
Robert Millikan experimented with oil drops to determine a value for the electronic charge. Figure 4 shows a stationary oil droplet between two horizontal metal pla... show full transcript
Step 1
Answer
The charge on the oil droplet is negative. When in a stationary state, the electric force acting on the droplet due to the electric field created by the positively charged upper plate is equal and opposite to the gravitational force acting downward. Therefore, the electric force acts upwards, indicating the charge on the droplet is negative as it is attracted towards the positive plate.
Step 2
Answer
To find the mass of the oil droplet, we can use the relationship for terminal velocity:
given that:
Calculating the radius using the volume for a sphere, , gives us the radius. Substituting the appropriate values into the equation yields:
After calculation, the mass m is found to be approximately .
Step 3
Answer
Using the balance of forces on the droplet when it is rising at constant speed:
At rising speed, the electric force is acting, where is the electric field.
Setting the net force to zero gives:
From this, we can express the relationship:
Rearranging this, we obtain:
Thus:
Step 4
Answer
Substituting known values from previous parts provides:
By using these values in the derived equation, the charge Q can be calculated. Comparing this value with the accepted value of the electronic charge () determines if it is consistent. If discrepancies exist, the reasoning must be retraced to identify potential calculation errors.
Step 5
Answer
Errors in measuring the viscosity of air would influence the calculated terminal velocities and consequently the mass of the oil droplet. A smaller value for viscosity would lead to a smaller calculated mass and charge. This underestimation would result in Millikan's value for the electronic charge appearing larger than its true value, thus impacting the accuracy and reliability of his conclusions about the charge of the electron.
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