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Figure 6 shows a rotating spacecraft that is proposed to carry astronauts to Mars - AQA - A-Level Physics - Question 4 - 2021 - Paper 1

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Figure 6 shows a rotating spacecraft that is proposed to carry astronauts to Mars. The spacecraft consists of two parts A and B connected by a rigid cylindrical rod... show full transcript

Worked Solution & Example Answer:Figure 6 shows a rotating spacecraft that is proposed to carry astronauts to Mars - AQA - A-Level Physics - Question 4 - 2021 - Paper 1

Step 1

Explain why.

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Answer

As the spacecraft rotates, the centripetal force acts inward towards the center of rotation. This force mimics the effect of gravity on the astronauts, pressing them against the floor, providing them with a sensation similar to gravitational pull.

Step 2

Show, by considering the centripetal forces acting on A and B, that $r_A$ is given by $\frac{m_b L}{m_a + m_b}$.

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Answer

To derive the relationship for rAr_A, we can equate the centripetal force acting on both A and B. The centripetal force for mass A is given by FA=mavA2rAF_A = m_a \frac{v_A^2}{r_A} and for mass B, FB=mbvB2rBF_B = m_b \frac{v_B^2}{r_B}. As both parts are connected, the angular velocities (ω\omega) are the same, and we have:

vA=ωrAv_A = \omega r_A
vB=ωrBv_B = \omega r_B

By substituting vAv_A and vBv_B into the centripetal force equations, equating forces, and considering that the distances relate by rA+rB=Lr_A + r_B = L, we arrive at the equation for rAr_A as follows:

rA=mbLma+mb.r_A = \frac{m_b L}{m_a + m_b}.

Step 3

Deduce whether the centre of mass of A or the centre of mass of B rotates with a greater linear speed.

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Answer

Since ma<mbm_a < m_b, it follows that rA<rBr_A < r_B. Given that linear speed (vv) relates to the radius of rotation, the linear speed of A (which is closer to the center of mass) will be lower than that of B. Thus, the centre of mass of B rotates with a greater linear speed.

Step 4

Suggest a suitable diameter for the rod. Justify your answer.

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Answer

To suggest a suitable diameter for the rod, we must consider the maximum stress the rod can endure. The safety factor should be taken into account, with the maximum stress for the material being less than 300 GPa from the stress-strain curve. Given the loaded conditions, we can calculate the stress exerted on the rod using:

Stress=FA\text{Stress} = \frac{F}{A}

Where FF is the force and A=πd24A = \frac{\pi d^2}{4}. By rearranging and substituting the appropriate values, we can estimate an appropriate diameter ensuring it does not exceed the material's maximum stress capacity. A calculated diameter in the range of 0.01m (10mm) may be suitable, ensuring ample safety and structural integrity under load.

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