Figure 7 shows a system to monitor a tank filling with liquid in which a magnet is mounted on a float - AQA - A-Level Physics - Question 3 - 2019 - Paper 8
Question 3
Figure 7 shows a system to monitor a tank filling with liquid in which a magnet is mounted on a float.
The Hall effect sensor produces an output voltage $V$. $V$ de... show full transcript
Worked Solution & Example Answer:Figure 7 shows a system to monitor a tank filling with liquid in which a magnet is mounted on a float - AQA - A-Level Physics - Question 3 - 2019 - Paper 8
Step 1
Compare the advantages of the two arrangements for monitoring the movement of the magnet towards the Hall effect sensor.
96%
114 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
With the north pole facing the sensor:
Higher sensitivity and larger gradient over very short range.
There is some ambiguity in liquid level due to peak in graph, meaning it may not correctly reference a single output reading.
With the south pole facing the sensor:
Less sensitivity and smaller gradient but covers a larger range.
There is no ambiguity in liquid level, since each level produces a discrete output up to saturation.
Step 2
Calculate the number of complete revolutions of the drive shaft in one second.
99%
104 rated
Only available for registered users.
Sign up now to view full answer, or log in if you already have an account!
Answer
From Figure 10, there are approximately 2.4 divisions (5 ms/div) per complete cycle. Thus, for the period T:
Period time = 2.4 divisions × 5 ms/div = 12 ms.
The frequency f can be found using the formula:
f=T1=12ms1=0.012s1=83.33Hz.
To find the number of revolutions in one second:
Number of revolutions = frequency × time = 83.33Hz×1s=83.33 rev.
Rounding down gives 83 full revolutions in one second.