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Figure 2 shows two magnets, supported on a yoke, placed on an electronic balance - AQA - A-Level Physics - Question 2 - 2017 - Paper 2

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Figure 2 shows two magnets, supported on a yoke, placed on an electronic balance. Figure 3 shows a simplified plan view of the copper wire and magnets. The magnets... show full transcript

Worked Solution & Example Answer:Figure 2 shows two magnets, supported on a yoke, placed on an electronic balance - AQA - A-Level Physics - Question 2 - 2017 - Paper 2

Step 1

Which of the following correctly describes the direction of the force acting on the wire DE due to the magnetic field when the switch is closed?

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Answer

The correct answer is: vertically up. According to Fleming's Left Hand Rule, the direction of the force is perpendicular to both the current and the magnetic field.

Step 2

Label the poles of the magnets by putting N or S on each of the two dashed lines in Figure 3.

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Answer

The left magnet should be labeled 'N' (North) and the right magnet 'S' (South). This configuration indicates the direction of the magnetic field from North to South.

Step 3

Define the tesla.

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Answer

The tesla (T) is the SI unit of magnetic flux density. It is defined as the amount of magnetic flux (measured in webers) passing through a unit area (measured in square meters) perpendicular to the direction of the magnetic field. One tesla is equivalent to one weber per square meter.

Step 4

Calculate the magnetic flux density between the magnets.

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Answer

Using the formula for magnetic force: B=FIlB = \frac{F}{I \cdot l}, where ( F = mg ) with ( m = 0.620 g = 0.000620 kg ), ( g = 9.81 ,m/s^2 ), ( I = 3.43 , A ), and ( l = 0.0500 , m ):

  1. Calculate the force: F=0.000620kg9.81m/s2=0.0060782NF = 0.000620 \, kg \cdot 9.81 \, m/s^2 = 0.0060782 \, N

  2. Substitute into the formula for B: B=0.0060782N3.43A0.0500m=0.0350T0.036TB = \frac{0.0060782 \, N}{3.43 \, A \cdot 0.0500 \, m} = 0.0350 \, T \approx 0.036 \, T

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