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A thermal nuclear reactor uses a moderator to lower the kinetic energy of fast-moving neutrons - AQA - A-Level Physics - Question 6 - 2019 - Paper 2

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A thermal nuclear reactor uses a moderator to lower the kinetic energy of fast-moving neutrons. A neutron has an initial kinetic energy of 2.0 MeV. Calculate the k... show full transcript

Worked Solution & Example Answer:A thermal nuclear reactor uses a moderator to lower the kinetic energy of fast-moving neutrons - AQA - A-Level Physics - Question 6 - 2019 - Paper 2

Step 1

Explain why the kinetic energy of neutrons must be reduced in a thermal nuclear reactor.

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Answer

The kinetic energy of neutrons needs to be reduced to increase the probability of neutron absorption by fissile materials like U-235. Lower kinetic energy allows neutrons to interact more effectively with atomic nuclei, facilitating nuclear fission.

Step 2

Calculate the kinetic energy of the neutron after five collisions.

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Answer

After each collision, a neutron loses 63% of its kinetic energy. Therefore, after one collision, the new energy is:

E1=0.37×E0E_1 = 0.37 \times E_0

For 5 collisions, the kinetic energy is calculated using:

E5=E0×(0.37)5E_5 = E_0 \times (0.37)^5

Substituting E0=2.0MeVE_0 = 2.0 \, MeV:

E5=2.0MeV×(0.37)50.25MeVE_5 = 2.0 \, MeV \times (0.37)^5 \approx 0.25 \, MeV

Step 3

Explain why the number of collisions needed to do this depends on the nucleon number of the moderator atoms.

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Answer

The number of collisions required for a neutron to lose energy to a specific level is influenced by the nucleon number of the moderator. A higher nucleon number can lead to a greater likelihood of effective collisions, as more nuclei are available to interact with the neutron. Thus, moderators with a higher nucleon number can decrease neutron energy more efficiently.

Step 4

Calculate in MeV the energy released in this fission process.

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Answer

To calculate the energy released during the fission process, we use the mass-energy equivalence principle:

  1. Calculate the mass difference:

Δm=(massinitial)(massfinal)\Delta m = (mass_{initial}) - (mass_{final})

Where:

  • massinitial=235.044+1.0087umass_{initial} = 235.044 + 1.0087 \, u
  • massfinal=141.930+89.908+4(1.0087)umass_{final} = 141.930 + 89.908 + 4(1.0087) \, u
  1. Substituting values: Δm=(236.0527141.93089.9084.0348)u0.0809u\Delta m = (236.0527 - 141.930 - 89.908 - 4.0348) \, u \approx 0.0809 \, u

  2. Convert mass difference to energy using: E=Δmc2=0.0809u931.5MeV/u75.4MeVE = \Delta m \cdot c^2 = 0.0809 \, u \cdot 931.5 \, MeV/u \approx 75.4 \, MeV

Step 5

State three benefits of using nuclear power.

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Answer

  1. Low Greenhouse Gas Emissions: Nuclear power generates electricity with minimal greenhouse gas emissions, contributing to climate change mitigation.
  2. High Energy Density: Nuclear fuel contains a large amount of energy in a small volume compared to fossil fuels.
  3. Reliability and Consistency: Nuclear power plants provide stable and continuous energy supply, unlike some renewable energy sources that may be intermittent.

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