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Question 3
Figure 4 shows the structure of a violin and Figure 5 shows a close-up image of the tuning pegs. The strings are fixed at end A. The strings pass over a bridge and ... show full transcript
Step 1
Answer
A stationary wave on a stretched string is produced when waves traveling in opposite directions interfere with each other. When the string is plucked, waves travel away from the point of plucking towards the fixed ends. At the fixed ends, these waves reflect back, creating new waves.
The interference between the incoming and reflected waves results in stationary waves, characterized by nodes (points of no displacement) and antinodes (points of maximum displacement). The fixed endpoints serve as nodes, while the points between them can become antinodes, leading to a standing wave formation.
Step 2
Answer
To determine the mass of the 1.0 m length of the string, we can use the relationship between tension, frequency, and the mass per unit length.
Starting with the formula for the frequency of a vibrating string: where:
Rearranging this yields: We can now plug in the values: .
Step 3
Answer
The wave speed on a string can be calculated using the formula: where:
Calculating the wavelength:
Now calculating wave speed: .
Step 4
Answer
To determine the higher frequency produced after stretching the string, we first need to calculate the new tension after the angle of rotation affects the effective length. The extension due to turning can be estimated based on the diameter and rotation:
The circumference of the circular peg is calculated as:
The effective extension of the string when tightened can be calculated as:
Adding this to the original length:
Now, the new tension can then be recalculated using:
Using the new length and the relation for frequency:
After completing the calculations, the higher produced frequency will be determined, potentially ending up between 448 Hz and 455 Hz.
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