Photo AI
Question 1
Figure 1 shows the apparatus used in an experiment to investigate electron diffraction and the de Broglie hypothesis. Explain how high-speed electrons are produced ... show full transcript
Step 1
Answer
Part A is the heated cathode, which emits electrons due to thermionic emission when heated. Part B is the anode, which is positively charged to attract the emitted electrons. The potential difference provides the energy to heat the cathode, ensuring a sufficient current of electrons is emitted. The potential difference accelerates the emitted electrons towards the target.
Step 2
Answer
Given that the atom diameter is approximately 0.1 nm (or m), the corresponding wavelength for electron diffraction can be calculated using the de Broglie equation: ext{wavelength} = rac{h}{p} = rac{h}{mv} Assuming a suitable momentum relationship, a suitable potential difference can be found using the formula: This will yield a value for electrons with the required wavelength, which should be around . The exact value may vary based on additional parameters.
Step 3
Answer
The de Broglie hypothesis posits that particles, such as electrons, exhibit wave-like properties. By measuring the diffraction pattern produced when electrons pass through a crystalline target, we can observe the wave properties of electrons. The wavelength derived from electron energy can be compared to the observed diffraction patterns, providing experimental support for the wave-particle duality concept. These measurements illustrate the predicted relationships between wavelength and momentum, reinforcing de Broglie's theory.
Step 4
Answer
For STM: Moving electrons can cross a potential barrier. For TEM: Moving electrons can be deflected by a magnetic field.
Note: Tick the appropriate box linking each type of microscope to the indicated properties.
Report Improved Results
Recommend to friends
Students Supported
Questions answered