Which combination of properties would produce the smallest extension of a wire when the same tensile force is applied to the wire?
| Cross-sectional area | Length | Young modulus of material |
|---------------------|--------|--------------------------|
| A | X | 3L | E |
| B | 2X | L | E |
| C | X | 3L | 4E |
| D | 2X | L | 4E | - AQA - A-Level Physics - Question 20 - 2019 - Paper 1
Question 20
Which combination of properties would produce the smallest extension of a wire when the same tensile force is applied to the wire?
| Cross-sectional area | Length |... show full transcript
Worked Solution & Example Answer:Which combination of properties would produce the smallest extension of a wire when the same tensile force is applied to the wire?
| Cross-sectional area | Length | Young modulus of material |
|---------------------|--------|--------------------------|
| A | X | 3L | E |
| B | 2X | L | E |
| C | X | 3L | 4E |
| D | 2X | L | 4E | - AQA - A-Level Physics - Question 20 - 2019 - Paper 1
Step 1
Cross-sectional area: 2X, Length: L, Young modulus of material: 4E
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Answer
To determine which combination produces the smallest extension, we can use the formula for extension:
extExtension=AYFL
where:
F is the tensile force,
L is the length,
A is the cross-sectional area,
Y is the Young's modulus of the material.
From the options:
In option D: The cross-sectional area is doubled (2X), the length is L, and the Young modulus is quadrupled (4E). This maximizes the resistance to extension. The resulting extension willbe as follows:
extExtensionD=2X⋅4EF⋅L=8XEF
In contrast, the other options will yield greater extensions due to lower areas or lower Young's moduli.
Thus, option D gives the smallest extension under the same tensile force.