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Figure 1 shows an electric steam iron - AQA - A-Level Physics - Question 1 - 2022 - Paper 2

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Figure 1 shows an electric steam iron. Water from a reservoir drips onto an electrically-heated metal plate. The water boils and steam escapes through holes in the ... show full transcript

Worked Solution & Example Answer:Figure 1 shows an electric steam iron - AQA - A-Level Physics - Question 1 - 2022 - Paper 2

Step 1

Calculate t.

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Answer

To find the time t taken for the metal plate to reach its working temperature, we can use the formula for heat transfer: Q=mcriangleTQ = mc riangle T Where:

  • QQ is the heat energy (in Joules),
  • mm is the mass of the metal plate (1.2 kg),
  • cc is the specific heat capacity of the metal (450 J kg⁻¹ K⁻¹), and
  • riangleT riangle T is the change in temperature.

Given that the initial temperature is 20 °C and the final temperature is 125 °C, we find riangleT riangle T: riangleT=125°C20°C=105°C riangle T = 125 °C - 20 °C = 105 °C

Now substituting the values: Q=1.2imes450imes105Q = 1.2 imes 450 imes 105 Q=63000extJQ = 63000 ext{ J}

Since the power of the heater is 2.1 kW (or 2100 W), we can relate energy and power to time:

ightarrow t = \frac{Q}{P}$$ t = \frac{63000}{2100} \ &t \approx 30 ext{ seconds}.

Step 2

Determine whether this claim is true.

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Answer

To verify whether the iron can generate steam at a rate of 60 g min⁻¹, we first convert this to kg: 60 g min⁻¹ = 0.06 kg min⁻¹.

Now, using the specific latent heat of vaporization of water, we calculate the energy required to convert 0.06 kg of water into steam: Qsteam=mLQ_{steam} = mL
where

  • m=0.06extkgm = 0.06 ext{ kg}, and
  • L=2.3imes105extJkg1L = 2.3 imes 10^5 ext{ J kg}^{-1}. \

Substituting these values: Qsteam=0.06imes2.3imes105Q_{steam} = 0.06 imes 2.3 imes 10^5

Next, we determine how much power is available for vaporization. Since the power of the heater is 2100 W, the energy available in one minute is: Qavailable=Pimestime=2100imes60=126000extJQ_{available} = P imes time = 2100 imes 60 = 126000 ext{ J}

Since Qavailable(126000extJ)>Qsteam(13800extJ)Q_{available} (126000 ext{ J}) > Q_{steam} (13800 ext{ J}), the claim is true as the energy supplied is sufficient to produce 60 g of steam per minute.

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