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Figure 1 shows a perfectly insulated cylinder containing 0.050 kg of liquid nitrogen at a temperature of 70 K - AQA - A-Level Physics - Question 1 - 2019 - Paper 2

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Figure 1 shows a perfectly insulated cylinder containing 0.050 kg of liquid nitrogen at a temperature of 70 K. A heater transfers energy at a constant rate of 12 W t... show full transcript

Worked Solution & Example Answer:Figure 1 shows a perfectly insulated cylinder containing 0.050 kg of liquid nitrogen at a temperature of 70 K - AQA - A-Level Physics - Question 1 - 2019 - Paper 2

Step 1

Calculate the Specific Heat Capacity of Liquid Nitrogen

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Answer

To calculate the specific heat capacity (cc) of liquid nitrogen, we first need to determine the total energy supplied to the nitrogen:

  1. Total Energy Supplied (EtE_t):

    Et=Pimest=12extWimes890exts=10680extJE_t = P imes t = 12 ext{ W} imes 890 ext{ s} = 10680 ext{ J}

  2. Energy Required to Heat Liquid Nitrogen to Boiling Point:

    Since we are heating the nitrogen from its initial temperature (70 K) to its boiling point (77 K), we will need to calculate the temperature difference (riangleT riangle T).

    riangleT=77extK70extK=7extK riangle T = 77 ext{ K} - 70 ext{ K} = 7 ext{ K}

  3. Calculate the Specific Heat Capacity (cc):

    The specific heat capacity can be calculated using the formula:

    c = rac{E}{m imes riangle T}

    Where,

    • EE = total energy supplied = 10680 J
    • mm = mass of nitrogen = 0.050 kg

    Substituting the values:

    c = rac{10680 ext{ J}}{0.050 ext{ kg} imes 7 ext{ K}} = rac{10680}{0.35} ext{ J kg}^{-1} ext{ K}^{-1} = 30514.29 ext{ J kg}^{-1} ext{ K}^{-1}

    Therefore, the specific heat capacity of liquid nitrogen is approximately 30500 J kg^{-1} K^{-1}.

Step 2

Determine Work Done (X) and Energy Required (Y)

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Answer

  1. Work Done by Nitrogen (XX):

    The work done by the nitrogen during expansion can be calculated using the formula:

    X=PimesriangleVX = P imes riangle V

    Assuming an approximate volume change with negligible contributions and density considerations, calculate accordingly when the change state occurs from liquid to gas.

  2. Energy Required to Change State (YY):

    The energy required for the phase change of nitrogen from a liquid to a gas is given by the specific latent heat of vaporization:

    Y=mimesL=0.050extkgimes2.0imes105extJkg1=10000extJY = m imes L = 0.050 ext{ kg} imes 2.0 imes 10^5 ext{ J kg}^{-1} = 10000 ext{ J}

  3. Compare X and Y:

    Given that the density of the gas at the boiling point (3.8 kg m^{-3}) is significantly lower than that of the liquid (810 kg m^{-3}), it can be inferred that the volume change during the state transition may lead to greater instantaneous work done (WightarrowXW ightarrow X being nearly negligible compared to YY). Hence,

    X<YX < Y Thus the energy required to change the state of nitrogen is greater than the work done during the process.

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