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A mobile phone operates at a constant power of 200 mW It has a 3.7 V lithium-ion battery that has a charge capacity of 9400 C What is the time taken for the battery to discharge completely? - AQA - A-Level Physics - Question 26 - 2018 - Paper 1

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Question 26

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A mobile phone operates at a constant power of 200 mW It has a 3.7 V lithium-ion battery that has a charge capacity of 9400 C What is the time taken for the battery ... show full transcript

Worked Solution & Example Answer:A mobile phone operates at a constant power of 200 mW It has a 3.7 V lithium-ion battery that has a charge capacity of 9400 C What is the time taken for the battery to discharge completely? - AQA - A-Level Physics - Question 26 - 2018 - Paper 1

Step 1

Calculate the energy stored in the battery

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Answer

The energy (E) stored in the battery can be calculated using the formula:

E=VimesQE = V imes Q

where:

  • VV is the voltage (3.7 V)
  • QQ is the charge capacity (9400 C)

Thus,

E=3.7extVimes9400extC=34680extJE = 3.7 ext{ V} imes 9400 ext{ C} = 34680 ext{ J}

Step 2

Calculate the time taken to discharge completely

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Answer

The time (t) taken to discharge the battery can be calculated using the formula:

t=EPt = \frac{E}{P}

where:

  • EE is the energy (34680 J)
  • PP is the power (200 mW or 0.2 W)

Now substituting the values:

t=34680extJ0.2extW=173400extsecondst = \frac{34680 ext{ J}}{0.2 ext{ W}} = 173400 ext{ seconds}

To convert seconds into hours:

173400extseconds÷360048.25exthours173400 ext{ seconds} \div 3600 \approx 48.25 ext{ hours}

Thus, the time taken for the battery to discharge completely is approximately 48 hours.

Step 3

Select the correct answer

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Answer

Based on the calculation, the correct option is B. 48 hours.

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