A tennis ball has a mass of 58 g - AQA - A-Level Physics - Question 26 - 2022 - Paper 1

Now, we calculate the momentum of the ball just after rebounding to a height of 1.1 m:

Similarly, the velocity just after rebounding can be calculated using: $v' = ext{sqrt}(2gh') = ext{sqrt}(2 \times 9.81 \times 1.1)$

Substituting the values, we find: $v' \approx 4.67 ext{ m/s}.$

Thus, the momentum just after rebounding is: $$p' = mv' = 0.058 \times 4.67 = 0.271 ext{ kg m/s}.$

Finally, the change in momentum ( Δp) during the collision is calculatedas:

$\Delta p = p' - (-p) = 0.271 - (-0.341) = 0.271 + 0.341 = 0.612 ext{ kg m/s}.$

Thus, the change in momentum of the ball during its collision with the ground is approximately 0.614 N s.