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The reaction between 1-chloro-1-phenylethane and hydroxide ions to produce 1-phenylethanol is: C₆H₅CHClCH₃ + OH⁻ → C₆H₅CH(OH)CH₃ + Cl⁻ The rate of this reaction can be studied by measuring the amount of hydroxide ions that remain in solution at a given time - CIE - A-Level Chemistry - Question 6 - 2017 - Paper 1

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The-reaction-between-1-chloro-1-phenylethane-and-hydroxide-ions-to-produce-1-phenylethanol-is:--C₆H₅CHClCH₃-+-OH⁻-→-C₆H₅CH(OH)CH₃-+-Cl⁻--The-rate-of-this-reaction-can-be-studied-by-measuring-the-amount-of-hydroxide-ions-that-remain-in-solution-at-a-given-time-CIE-A-Level Chemistry-Question 6-2017-Paper 1.png

The reaction between 1-chloro-1-phenylethane and hydroxide ions to produce 1-phenylethanol is: C₆H₅CHClCH₃ + OH⁻ → C₆H₅CH(OH)CH₃ + Cl⁻ The rate of this reaction ca... show full transcript

Worked Solution & Example Answer:The reaction between 1-chloro-1-phenylethane and hydroxide ions to produce 1-phenylethanol is: C₆H₅CHClCH₃ + OH⁻ → C₆H₅CH(OH)CH₃ + Cl⁻ The rate of this reaction can be studied by measuring the amount of hydroxide ions that remain in solution at a given time - CIE - A-Level Chemistry - Question 6 - 2017 - Paper 1

Step 1

Describe a suitable method for studying the rate of this reaction at a temperature of 40°C.

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Answer

To study the reaction rate:

  1. Prepare solutions A (0.10mol dm⁻³ 1-chloro-1-phenylethane) and B (0.10mol dm⁻³ sodium hydroxide) in separate volumetric flasks.
  2. Place both solutions in an ice-bath at 40°C to ensure they are at the required temperature before mixing.
  3. Measure equal volumes of solutions A and B and mix them together rapidly in a reaction vessel.
  4. Use a stopcock to draw a sample at known time intervals to monitor the concentration of hydroxide ions remaining.
  5. Dilute the reaction mixture with an ice-cold solvent to stop the reaction, ensuring accurate rate measurements can be made.
  6. Use back-titration with HCl to determine the amount of hydroxide ions remaining at each time interval.

Step 2

Deduce the order of reaction with respect to each [C₆H₅CHClCH₃] and [OH⁻].

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Answer

To analyze the order of reaction:

  • From experiments 1 to 2, when [C₆H₅CHClCH₃] is doubled, the relative rate doubles, indicating that the order with respect to [C₆H₅CHClCH₃] is 1.
  • From experiments 2 and 3, when [OH⁻] is doubled and [C₆H₅CHClCH₃] remains constant, the relative rate does not double, suggesting that the order with respect to [OH⁻] is 0.

Step 3

Calculate the relative rate for experiment 4.

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Answer

From the data provided:

  • Using the relationship determined from previous experiments, we observe that if the concentrations in experiment 4 are used in conjunction with known relative rates from experiments 1 and 2, we can calculate the relative rate. If the stoichiometric relationships hold true, and considering the concentrations used, the estimated relative rate for experiment 4 is 2.0.

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