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Dinitrogen tetraoxide, N2O4, and nitrogen dioxide, NO2, exist in dynamic equilibrium with each other - CIE - A-Level Chemistry - Question 2 - 2016 - Paper 1

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Dinitrogen tetraoxide, N2O4, and nitrogen dioxide, NO2, exist in dynamic equilibrium with each other. The energy profile for this reaction is shown. (a) Add labell... show full transcript

Worked Solution & Example Answer:Dinitrogen tetraoxide, N2O4, and nitrogen dioxide, NO2, exist in dynamic equilibrium with each other - CIE - A-Level Chemistry - Question 2 - 2016 - Paper 1

Step 1

Add labelled arrows to the energy profile to indicate the enthalpy change of the reaction, ΔH

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Answer

Draw an arrow vertically upward from the N2O4 line to the 2NO2 line, and label it as ΔH.

Step 2

Add labelled arrows to the energy profile to indicate the activation energy of the forward reaction, Eᵪ

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Answer

Draw an arrow vertically upward from the N2O4 line to the peak of the energy profile, and label it as Eᵪ.

Step 3

Calculate the average molecular mass, Mᵢ, of the resulting equilibrium mixture.

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Answer

To find the average molecular mass, use the formula:
Mi=mp×VM_i = \frac{m}{p \times V}
where:

  • m = mass of the equilibrium mixture = 4.606 g
  • p = pressure = 1.68 \times 10^{2} , ext{Pa}
  • V = volume = 1.00 , ext{dm}^3 = 1.00 \times 10^{-3} , ext{m}^3
    Now substituting the values:
    Mi=4.606extg×831.3231.68×102imes1.00×103=73.6 g mol1M_i = \frac{4.606 \, ext{g} \times 831.323}{1.68 \times 10^{2} imes 1.00 \times 10^{-3}} = 73.6 \text{ g mol}^{-1}

Step 4

State, in terms of n, the amount, in moles, of NO2 in the equilibrium mixture.

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Answer

The amount of NO2 can be expressed as:
n + 2n = 2n
x = 2n.

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