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Cobalt is a transition element that forms complex ions with oxidation states +2 and +3 - CIE - A-Level Chemistry - Question 4 - 2016 - Paper 1

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Cobalt is a transition element that forms complex ions with oxidation states +2 and +3. Explain what is meant by the term transition element. The following scheme s... show full transcript

Worked Solution & Example Answer:Cobalt is a transition element that forms complex ions with oxidation states +2 and +3 - CIE - A-Level Chemistry - Question 4 - 2016 - Paper 1

Step 1

Explain what is meant by the term transition element.

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Answer

A transition element is defined as an element that forms one or more stable ions or compounds with partially filled d orbitals. These elements are typically characterized by their ability to engage in complex formation and exhibit various oxidation states.

Step 2

State the formula of A.

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Answer

[Co(OH)6]2−

Step 3

State the formula of B.

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Answer

[Co(H2O)6]2+

Step 4

State the formula of C.

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Answer

[Co(NH3)6]3+

Step 5

State the colour of the following solutions.

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Answer

[Co(H2O)6]2+: Blue solution of B: Pink solution of C: Yellow/orange

Step 6

Define the term standard electrode potential.

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Answer

The standard electrode potential (E°) is the emf (electromotive force) of an electrochemical cell under standard conditions, defined as 1 mol dm−3 concentration of all species and a pressure of 1 atm at a temperature of 298 K.

Step 7

Complete the table with the substance used to make the electrode.

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Answer

half-cell | electrode Co2+/Co | Co/cobalt Fe2+/Fe | Pt/carbon/graphite

Step 8

Write the equation for the overall cell reaction.

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Answer

Co2+ + 2e− ⇌ Co(s)

Step 9

Use the Data Booklet to calculate the E°cell.

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Answer

E°cell = 0.77 - 0.28 - 0.77 - 1.05 = -0.18 V

Step 10

Use the Data Booklet and the Nernst equation to calculate the value of E for the Co2+/Co half-cell.

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Answer

E for Co2+/Co = E° + (0.059/2) log [0.050] = -0.18 + (0.059/2) log(0.050) = -0.18 + 0.059/2 * (−1.3010) = -0.18 + 0.059 * (−0.6505) = -0.18 - 0.0383 ≈ -0.2183 V

Step 11

Suggest how this change will affect the overall cell potential.

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Answer

More positive

Step 12

Write an equation for the reaction of iron(III) ions with vanadium metal.

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Answer

4Fe3+(aq) + V(s) → 4Fe2+(aq) + V4+(aq) + 2e−

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