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The end A of a uniform rod AB, of length 2a and weight W, is freely hinged to a vertical wall - CIE - A-Level Further Maths - Question 11 - 2016 - Paper 1

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The end A of a uniform rod AB, of length 2a and weight W, is freely hinged to a vertical wall. The end B of the rod is attached to a light elastic string of natural ... show full transcript

Worked Solution & Example Answer:The end A of a uniform rod AB, of length 2a and weight W, is freely hinged to a vertical wall - CIE - A-Level Further Maths - Question 11 - 2016 - Paper 1

Step 1

Find the angle between AB and CA produced by θ

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Answer

Denote the angle between AB and CA produced by θ and the midpoint of BC by E. Using the geometry of the setup, we identify that:

  1. Angle EAB (which is θ) is required as part of our calculations, for which we shall denote it as θ.
  2. In triangle ABC, we can express the relationships in terms of the lengths and trigonometric ratios.

Step 2

Find tension T in terms of W

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Answer

We start by substituting the lengths:

  • The length AB = 2a and AE = 2a sin(θ).
  • The weight W acts vertically downward at point A.

Taking moments about A, we have: ext{T} imes rac{3}{2}a imes ext{sin } heta = W imes 2a

Solving this for tension T gives: T = rac{W imes 4}{3 imes ext{sin } heta}

Step 3

Find the magnitude of the reaction force at A

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Answer

At point A, we can find the vertical force Y and horizontal force X:

  1. The vertical force Y can be expressed as: Y=W+TimesextcoshetaY = W + T imes ext{cos } heta

  2. The horizontal force X can be found as the component of the tension acting horizontally: X=TimesextsinhetaX = T imes ext{sin } heta

  3. To find the magnitude of the reaction force at A: RA=extsqrt(Y2+X2)R_A = ext{sqrt}(Y^2 + X^2). Substitute the expressions for Y and X to get the final answer.

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