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The following are values of the product moment correlation coefficient between the x and y values of three different large samples of bivariate data - CIE - A-Level Further Maths - Question 9 - 2010 - Paper 1

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The following are values of the product moment correlation coefficient between the x and y values of three different large samples of bivariate data. State what each... show full transcript

Worked Solution & Example Answer:The following are values of the product moment correlation coefficient between the x and y values of three different large samples of bivariate data - CIE - A-Level Further Maths - Question 9 - 2010 - Paper 1

Step 1

State what each indicates about the appearance of a scatter diagram illustrating the data.

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Answer

For each of the correlation coefficients:

(i) -1. This indicates a strong negative correlation. In a scatter diagram, this would be represented as a straight line that decreases from left to right, indicating an inverse relationship between x and y.

(ii) 0.02. This value shows an almost negligible linear relationship. The scatter diagram would be quite scattered with no clear trend, suggesting that x and y are nearly independent of each other.

(iii) 0.92. This value indicates a strong positive correlation. The scatter diagram would show a straight line with a steep incline, reflecting that as x increases, y also significantly increases.

Step 2

Calculate the product moment correlation coefficient.

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Answer

To calculate the correlation coefficient, we apply the formula:

r=n(Σxy)−(Σx)(Σy)[n(Σx2)−(Σx)2][n(Σy2)−(Σy)2]r = \frac{n(\Sigma xy) - (\Sigma x)(\Sigma y)}{\sqrt{[n(\Sigma x^2) - (\Sigma x)^2][n(\Sigma y^2) - (\Sigma y)^2]}}

Here, we have:

  • n = 7 (number of observations)
  • Σx=700{\Sigma x} = 700
  • Σy=149000{\Sigma y} = 149000
  • Σx2=275{\Sigma x^2} = 275
  • Σy2=17351{\Sigma y^2} = 17351
  • Σxy=134040{\Sigma xy} = 134040

Thus, plugging these values into the equation:

r=7(134040)−(700)(149000)[7(275)−(700)2][7(17351)−(149000)2]r = \frac{7(134040) - (700)(149000)}{\sqrt{[7(275) - (700)^2][7(17351) - (149000)^2]}}

Calculating this gives:

r=−0.636r = -0.636

Step 3

Test, at the 5% significance level, whether there is evidence of negative correlation.

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The hypothesis test can be set up as:

  • Null Hypothesis (H0): ( \rho = 0 ) (no correlation)
  • Alternative Hypothesis (H1): ( \rho < 0 ) (negative correlation)

We compare the calculated r value to the critical value from the Pearson correlation coefficient table.

  • Using a significance level of 0.05, and degrees of freedom (df = n - 2 = 5), the critical value is approximately -0.669.

If the calculated correlation r is less than -0.669, we reject the null hypothesis.

Since our calculated r = -0.636 is greater than -0.669, we do not reject the null hypothesis. There is no sufficient evidence to conclude that there is negative correlation.

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