A car moves along a horizontal straight road, passing two points A and B - Edexcel - A-Level Maths Mechanics - Question 3 - 2008 - Paper 1

The total distance covered is 1 km = 1000 m.

From A to W, the average speed is: $\text{Average speed} = \frac{15 + 5}{2} = 10 \text{ m/s}$

Time taken from A to W: $t = \frac{120 ext{ m}}{10 \text{ m/s}} = 12 ext{ s}$

From W to the final point B, the car accelerates for 4 seconds (16 s - 12 s) and moves at constant speed for 22 seconds, totaling: $T = 12 + 4 + 22 = 38 \text{ s}$

Using the total distances covered:

The distance from A to W is 120 m and the distance covered while moving at V m/s over 22 seconds is given by: $D = V \times t = V \times 22$

Hence, $120 + 22V = 1000$

Solving the equation gives:

22V = 880\ V = \frac{880}{22} = 40 ext{ m/s}$$