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Question 7
Figure 4 shows a lorry of mass 1600 kg towing a car of mass 900 kg along a straight horizontal road. The two vehicles are joined by a light towbar which is at an ang... show full transcript
Step 1
Answer
To find the acceleration, we need to apply Newton's second law. The total force acting on the system is given by:
The total mass of both vehicles is:
Substituting numerical values:
Using Newton's second law, :
Therefore, the acceleration is:
a = rac{600}{2500} = 0.24 ext{ m s}^{-2}
Step 2
Answer
We can determine the tension in the towbar by analyzing the forces acting on the car. The forces acting on the car are the tension in the towbar (), the resistance (300 N), and the subsequent equation is:
Substituting known values gives:
Solving for :
Solving for using results in:
T = rac{516}{ ext{cos}(15^{ ext{°}})} o T ext{ approximately equals } 534 ext{ N}
Step 3
Answer
The car decelerates at a constant rate after the towbar breaks. The initial velocity and the final velocity . The only force acting on the car is the resistance, which is 300 N:
Using the equation of motion:
Where:
Substituting the values:
36 = -rac{2}{3} s$$ Thus: $$s = rac{36 imes 3}{2} = 54 ext{ m}$$Step 4
Answer
When the towbar breaks, the vertical component of tension () in the towbar is removed. This tension counteracts a portion of the weight of the car.
Without this upward force due to tension, the normal reaction force from the road on the car must increase to balance out the weight of the car. Therefore, it can be concluded that the normal reaction of the road on the car is increased.
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