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Two ships P and Q are moving along straight lines with constant velocities - Edexcel - A-Level Maths Mechanics - Question 4 - 2003 - Paper 1

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Two ships P and Q are moving along straight lines with constant velocities. Initially P is at a point O and the position vector of Q relative to O is (6i + 12j) km, ... show full transcript

Worked Solution & Example Answer:Two ships P and Q are moving along straight lines with constant velocities - Edexcel - A-Level Maths Mechanics - Question 4 - 2003 - Paper 1

Step 1

Find p and q in terms of t.

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Answer

The position vector of ship P at time t is given by:

p=10tjp = 10t j

The position vector of ship Q at time t is:

q=(68t)i+(12+6t)jq = (6 - 8t)i + (12 + 6t)j

Step 2

Calculate the distance of Q from P when t = 3.

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Answer

To find the distance between P and Q, we calculate:

PQ=qp=((68(3))i+(12+6(3))j)(0i+10(3)j)PQ = q - p = ((6 - 8(3))i + (12 + 6(3))j) - (0i + 10(3)j)

This results in:

PQ=(624)i+(12+1830)j=18i+0jPQ = (6 - 24)i + (12 + 18 - 30)j = -18i + 0j

The distance is:

PQ=extDistance=sqrt(18)2+02=18extkm|PQ| = ext{Distance} = \\sqrt{(-18)^2 + 0^2} = 18 ext{ km}

Step 3

Calculate the value of t when Q is due north of P.

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Answer

For Q to be due north of P, the x-component of q must equal zero:

68t=06 - 8t = 0

Solving for t:

8t=6    t=68=348t = 6\implies t = \frac{6}{8} = \frac{3}{4}

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