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Two particles P and Q have mass 0.4 kg and 0.6 kg respectively - Edexcel - A-Level Maths Mechanics - Question 1 - 2008 - Paper 1

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Two particles P and Q have mass 0.4 kg and 0.6 kg respectively. The particles are initially at rest on a smooth horizontal table. Particle P is given an impulse of m... show full transcript

Worked Solution & Example Answer:Two particles P and Q have mass 0.4 kg and 0.6 kg respectively - Edexcel - A-Level Maths Mechanics - Question 1 - 2008 - Paper 1

Step 1

Find the speed of P immediately before it collides with Q.

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Answer

The impulse given to particle P can be related to its motion using the formula:

I=mvI = mv

where:

  • II is the impulse (3 N s)
  • mm is the mass of particle P (0.4 kg)
  • vv is the speed of P before the collision.

Substituting the values, we have:

3=0.4v3 = 0.4 v

Solving for vv gives:

v=30.4=7.5 m s1v = \frac{3}{0.4} = 7.5 \text{ m s}^{-1}

Thus, the speed of P immediately before it collides with Q is 7.5 m s⁻¹.

Step 2

Show that immediately after the collision P is at rest.

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Answer

Using the principle of conservation of momentum, the total momentum before the collision must equal the total momentum after the collision.

Before the collision, the momentum of P is:

MomentumP=0.4×7.5=3 kg m s1\text{Momentum}_{P} = 0.4 \times 7.5 = 3 \text{ kg m s}^{-1}

The momentum of Q can be computed as:

MomentumQ=0.6×5=3 kg m s1\text{Momentum}_{Q} = 0.6 \times 5 = 3 \text{ kg m s}^{-1}

Let the speed of P after the collision be vv. Then, the total momentum after the collision is:

Total Momentumafter=0.4v+3\text{Total Momentum}_{after} = 0.4 v + 3

Setting the initial total momentum equal to the final total momentum gives:

3=0.4v+33 = 0.4 v + 3

Solving this equation leads to:

0.4v=00.4 v = 0

Thus, we find:

v=0v = 0

This confirms that immediately after the collision, particle P is at rest.

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