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Two particles, P and Q, have masses 2m and 3m respectively - Edexcel - A-Level Maths Mechanics - Question 2 - 2017 - Paper 1

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Two particles, P and Q, have masses 2m and 3m respectively. They are moving towards each other in opposite directions on a smooth horizontal plane when they collide ... show full transcript

Worked Solution & Example Answer:Two particles, P and Q, have masses 2m and 3m respectively - Edexcel - A-Level Maths Mechanics - Question 2 - 2017 - Paper 1

Step 1

Find the speed of P immediately after the collision.

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Answer

To find the speed of P immediately after the collision, we will apply the principle of conservation of momentum.

The total initial momentum before the collision can be expressed as:

pinitial=(2m)(4u)+(3m)(3u)=8mu9mu=mup_{initial} = (2m)(4u) + (3m)(-3u) = 8mu - 9mu = -mu

Let the speed of P after the collision be v. The total momentum after the collision is:

pfinal=(2m)v+(3m)(u)=2mv3mup_{final} = (2m)v + (3m)(-u) = 2mv - 3mu

Applying conservation of momentum gives us:

pinitial=pfinalp_{initial} = p_{final}

Thus,

mu=2mv3mu-mu = 2mv - 3mu

Rearranging this equation:

2mv=mu+3mu2mv = -mu + 3mu 2mv=2mu2mv = 2mu v=uv = u

Therefore, the speed of P immediately after the collision is u.

Step 2

State whether or not the direction of motion of P has been reversed by the collision.

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Answer

The direction of motion of P has been reversed by the collision. This is evident since the speed of P after the collision is now equal to u, indicating a change in its direction.

Step 3

Find the magnitude of the impulse exerted on P by Q in the collision.

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Answer

Impulse can be determined from the change in momentum of particle P. The impulse exerted on P by Q is given by:

I=extChangeinmomentum=m(vfinalvinitial)I = ext{Change in momentum} = m(v_{final} - v_{initial})

Using the values for P:

Initial momentum before the collision: pinitial=2m(4u)=8mup_{initial} = 2m(4u) = 8mu Final momentum after the collision: pfinal=2m(u)=2mup_{final} = 2m(u) = 2mu

Now calculating the impulse:

I=2mu8mu=6muI = 2mu - 8mu = -6mu

The magnitude of the impulse, which is the absolute value, is:

I=6mu|I| = 6mu

Therefore, the magnitude of the impulse exerted on P by Q in the collision is 6mu.

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