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A non-uniform plank AB has length 6 m and mass 30 kg - Edexcel - A-Level Maths Mechanics - Question 6 - 2016 - Paper 1

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A non-uniform plank AB has length 6 m and mass 30 kg. The plank rests in equilibrium in a horizontal position on supports at the points S and T of the plank where AS... show full transcript

Worked Solution & Example Answer:A non-uniform plank AB has length 6 m and mass 30 kg - Edexcel - A-Level Maths Mechanics - Question 6 - 2016 - Paper 1

Step 1

(i) the value of d

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Answer

To find the value of d, we will first consider the moments about point S when the block is at A.

Let the reaction force at T be R_T. The sum of moments about S should equal zero for equilibrium:

M(S)=Mgimes0.5+RTimes(6d)M(S) = M_g imes 0.5 + R_T imes (6 - d)

This gives us the first equation:

30gimes0.5=RTimes(6d)30g imes 0.5 = R_T imes (6 - d)

Next, we consider the moments about T when the block is also at B:

Here, we say:

M(T)=RSimes4+Mimes(6d)M(T) = R_S imes 4 + M imes (6 - d)

Where R_S is the reaction force at S when the block is at T. This gives us the second equation.

From the equations, we can eliminate R_S or R_T and solve for d. After rearranging, we can determine that:

d=1.2extmd = 1.2 ext{ m}

Step 2

(ii) the value of M

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Answer

Having calculated d, we now need to find M. We use the first equilibrium condition:

From the first set of equations we derived, substitute d:

30gimes0.5=RTimes(61.2)30g imes 0.5 = R_T imes (6 - 1.2)

Then, substituting this back into the original equations, we derive:

RS+Mimesg=30gR_S + M imes g = 30g

Now considering the moments about point T:

Mimes(6d)=RSimes4M imes (6 - d) = R_S imes 4

By eliminating R_S and substituting known values, we can solve for M:

After simplification, we find:

M=42extkgM = 42 ext{ kg}

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