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Two particles P and Q have mass 0.4 kg and 0.6 kg respectively - Edexcel - A-Level Maths Mechanics - Question 1 - 2008 - Paper 1

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Two particles P and Q have mass 0.4 kg and 0.6 kg respectively. The particles are initially at rest on a smooth horizontal table. Particle P is given an impulse of m... show full transcript

Worked Solution & Example Answer:Two particles P and Q have mass 0.4 kg and 0.6 kg respectively - Edexcel - A-Level Maths Mechanics - Question 1 - 2008 - Paper 1

Step 1

Find the speed of P immediately before it collides with Q.

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Answer

To find the speed of particle P before the collision, we can use the impulse-momentum theorem, which states that the impulse (I) equals the change in momentum (mv).

Given that:

  • Mass of P, m=0.4m = 0.4 kg
  • Impulse, I=3I = 3 N s

Using the formula: I=mvI = m v Substituting the values: 3=0.4v3 = 0.4 v

Solving for vv: v = rac{3}{0.4} = 7.5 ext{ m/s}

Thus, the speed of P immediately before it collides with Q is 7.5 m/s.

Step 2

Show that immediately after the collision P is at rest.

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Answer

Immediately after the collision, we know from the question that the speed of Q is 5 m/s.

Using the principle of conservation of momentum, the total momentum before the collision must equal the total momentum after the collision:

Before collision:

  • Momentum of P: 0.4imes7.5=30.4 imes 7.5 = 3 kg·m/s
  • Momentum of Q: 0.6imes0=00.6 imes 0 = 0 kg·m/s

Total momentum before: 3+0=33 + 0 = 3 kg·m/s

After collision (let the speed of P be vv):

  • Momentum of P: 0.4v0.4 v
  • Momentum of Q: 0.6imes5=30.6 imes 5 = 3 kg·m/s

Total momentum after: 0.4v+30.4v + 3

Setting the total momentum before and after equal: 3=0.4v+33 = 0.4v + 3 Solving for vv: 0.4v=00.4v = 0 v=0v = 0 Thus, particle P is at rest immediately after the collision.

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