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Question 1
Two particles P and Q have mass 0.4 kg and 0.6 kg respectively. The particles are initially at rest on a smooth horizontal table. Particle P is given an impulse of m... show full transcript
Step 1
Answer
To find the speed of particle P before the collision, we can use the impulse-momentum theorem, which states that the impulse (I) equals the change in momentum (mv).
Given that:
Using the formula: Substituting the values:
Solving for : v = rac{3}{0.4} = 7.5 ext{ m/s}
Thus, the speed of P immediately before it collides with Q is 7.5 m/s.
Step 2
Answer
Immediately after the collision, we know from the question that the speed of Q is 5 m/s.
Using the principle of conservation of momentum, the total momentum before the collision must equal the total momentum after the collision:
Before collision:
Total momentum before: kg·m/s
After collision (let the speed of P be ):
Total momentum after:
Setting the total momentum before and after equal: Solving for : Thus, particle P is at rest immediately after the collision.
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