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A bench consists of a plank which is resting in a horizontal position on two thin vertical legs - Edexcel - A-Level Maths Mechanics - Question 4 - 2009 - Paper 1

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A bench consists of a plank which is resting in a horizontal position on two thin vertical legs. The plank is modelled as a uniform rod $P S$ of length 2.4 m and mas... show full transcript

Worked Solution & Example Answer:A bench consists of a plank which is resting in a horizontal position on two thin vertical legs - Edexcel - A-Level Maths Mechanics - Question 4 - 2009 - Paper 1

Step 1

(a) the magnitude of the normal reaction between the plank and the leg at Q and the magnitude of the normal reaction between the plank and the leg at R

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Answer

Let the normal reactions at points QQ and RR be denoted as CC and DD respectively.

Using the equilibrium condition of moments about point RR: C+D=120extNC + D = 120 ext{ N}

Now applying the moment about QQ: M(Q)=80gimes0.8+40gimes0.440gimes0.4=Dimes1.6M(Q) = 80g imes 0.8 + 40g imes 0.4 - 40g imes 0.4 = D imes 1.6

This simplifies to: D=30gD = 30g

From the first equation, we then have: C=90gC = 90g

Thus, the normal reactions are:

  • At QQ: C=90gC = 90g N
  • At RR: D=30gD = 30g N.

Step 2

(b) find the distance QX

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Answer

Let the normal reaction at QQ when Arthur sits at XX be 2F2F and at RR be FF.

Applying the equilibrium condition: 2F+F=40g+20g+60g2F + F = 40g + 20g + 60g

Now setting the moment about point QQ: M(Q)=60gimes20g+20gimes0.4=40gimes0.4+Fimes1.6M(Q) = 60g imes 20g + 20g imes 0.4 = 40g imes 0.4 + F imes 1.6

From this setup, we can derive: QX = rac{16}{15} ext{ m} ext{ or } 1.07 ext{ m}.

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