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A rough plane is inclined to the horizontal at an angle $ heta$, where $ an heta = rac{3}{4}$ - Edexcel - A-Level Maths Mechanics - Question 1 - 2020 - Paper 1

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A rough plane is inclined to the horizontal at an angle $ heta$, where $ an heta = rac{3}{4}$. A brick P of mass m is placed on the plane. The coefficient of fri... show full transcript

Worked Solution & Example Answer:A rough plane is inclined to the horizontal at an angle $ heta$, where $ an heta = rac{3}{4}$ - Edexcel - A-Level Maths Mechanics - Question 1 - 2020 - Paper 1

Step 1

(a) find, in terms of m and g, the magnitude of the normal reaction of the plane on brick P

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Answer

To find the normal reaction, we first need to resolve the forces acting on brick P. The component of the weight acting perpendicular to the plane is given by:

R = mg imes rac{4}{5}

Therefore, the normal reaction RR is:

R = mg imes rac{4}{5}

Step 2

(b) show that μ = 3/4

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Answer

To show that the coefficient of friction u u is rac{3}{4}, we resolve the forces acting parallel to the plane. The force down the plane due to gravity is:

F = mg imes rac{3}{5}

In equilibrium, the frictional force is equal to the component of the weight down the plane:

u R$$ Substituting for $R$, we have: $$F_{friction} = u imes mg imes rac{4}{5}$$ Setting these equal: $$mg imes rac{3}{5} = u imes mg imes rac{4}{5}$$ Dividing both sides by $mg imes rac{4}{5}$ gives:

u = rac{3}{4}$$

Step 3

(c) Explain briefly why brick Q will remain at rest on the plane.

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Answer

The forces acting on brick Q will balance since the mass component mm cancels out. The friction between brick Q and the plane will increase in direct proportion to the weight component acting down the plane, thereby preventing any motion.

Step 4

(d) describe the motion of brick Q, giving a reason for your answer.

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Answer

Brick Q slides down the plane with constant speed. This indicates that there is no resultant force acting on it along the plane since the frictional force equals the component of its weight acting down the slope. As a result, there is no acceleration.

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