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A car of mass 1000 kg is towing a caravan of mass 750 kg along a straight horizontal road - Edexcel - A-Level Maths Mechanics - Question 2 - 2012 - Paper 1

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A car of mass 1000 kg is towing a caravan of mass 750 kg along a straight horizontal road. The caravan is connected to the car by a tow-bar which is parallel to the ... show full transcript

Worked Solution & Example Answer:A car of mass 1000 kg is towing a caravan of mass 750 kg along a straight horizontal road - Edexcel - A-Level Maths Mechanics - Question 2 - 2012 - Paper 1

Step 1

show that R=860

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Answer

To find R, we consider the entire system (car and caravan) as one unit. The total driving force is given as 3200 N. The total resistance force acting on the system includes the resistance of the caravan (R) and the resistance of the car (800 N).

Using Newton's second law, we can express the total force as: Fnet=mtotalimesaF_{net} = m_{total} imes a where:

  • mtotal=1000extkg+750extkg=1750extkgm_{total} = 1000 ext{ kg} + 750 ext{ kg} = 1750 ext{ kg}
  • a=0.88extm/s2a = 0.88 ext{ m/s}²
    Thus, we have: Fnet=1750imes0.88=1540extNF_{net} = 1750 imes 0.88 = 1540 ext{ N} Next, set up the equation based on the forces: 3200R800=15403200 - R - 800 = 1540 Solving this gives: R=32008001540=860extNR = 3200 - 800 - 1540 = 860 ext{ N}

Step 2

find the tension in the tow-bar

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Answer

To find the tension (T) in the tow-bar, we will analyze the forces acting specifically on the caravan. The net force acting on the caravan can be expressed as: RT=mcaravanimesaR - T = m_{caravan} imes a where:

  • mcaravan=750extkgm_{caravan} = 750 ext{ kg}
  • a=0.88extm/s2a = 0.88 ext{ m/s}²
    Substituting the values gives: 860T=750imes0.88860 - T = 750 imes 0.88 Calculating the right side yields: 750imes0.88=660extN750 imes 0.88 = 660 ext{ N} So the equation becomes: 860T=660860 - T = 660 Rearranging gives: T=860660=200extNT = 860 - 660 = 200 ext{ N}

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