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Two particles P and Q have mass 0.4 kg and 0.6 kg respectively - Edexcel - A-Level Maths Mechanics - Question 1 - 2008 - Paper 1

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Two particles P and Q have mass 0.4 kg and 0.6 kg respectively. The particles are initially at rest on a smooth horizontal table. Particle P is given an impulse of m... show full transcript

Worked Solution & Example Answer:Two particles P and Q have mass 0.4 kg and 0.6 kg respectively - Edexcel - A-Level Maths Mechanics - Question 1 - 2008 - Paper 1

Step 1

Find the speed of P immediately before it collides with Q.

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Answer

To find the speed of particle P before it collides with Q, we use the impulse-momentum theorem, which states that impulse equals the change in momentum.

Given that the impulse I is 3 N·s and the mass of particle P (m) is 0.4 kg, we can express this as:

I=mimesvI = m imes v

Thus:

3=0.4imesv3 = 0.4 imes v

Now, solve for v:

v=30.4=7.5ms1v = \frac{3}{0.4} = 7.5 \, \text{ms}^{-1}

Therefore, the speed of P immediately before it collides with Q is 7.5 m/s.

Step 2

Show that immediately after the collision P is at rest.

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Answer

To analyze the collision, we apply the principle of conservation of momentum.

Let v be the speed of P immediately after the collision. The momentum before the collision is equal to the momentum after the collision:

Before collision:

  • Momentum of P: (0.4 \times 7.5)
  • Momentum of Q: 0 (initially at rest)

Total momentum before = 0.4 \times 7.5 + 0 = 3.0 , \text{kg·m/s}

After collision:

  • Momentum of P: 0.4v
  • Momentum of Q: 0.6 \times 5

Total momentum after = (0.4v + 0.6 \times 5)

Setting these equal gives us:

3.0=0.4v+3.03.0 = 0.4v + 3.0

Rearranging this gives:

0.4v=3.03.0=00.4v = 3.0 - 3.0 = 0

Thus:

v=0v = 0

This shows that immediately after the collision, particle P is at rest.

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