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A railway truck P, of mass m kg, is moving along a straight horizontal track with speed 15 ms⁻¹ - Edexcel - A-Level Maths Mechanics - Question 1 - 2012 - Paper 1

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A railway truck P, of mass m kg, is moving along a straight horizontal track with speed 15 ms⁻¹. A truck P collides with a truck Q of mass 3000 kg, which is at res... show full transcript

Worked Solution & Example Answer:A railway truck P, of mass m kg, is moving along a straight horizontal track with speed 15 ms⁻¹ - Edexcel - A-Level Maths Mechanics - Question 1 - 2012 - Paper 1

Step 1

(a) the magnitude of the impulse exerted by P on Q.

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Answer

To find the impulse exerted by truck P on truck Q, we can use the formula for impulse:

I=extChangeinmomentumI = ext{Change in momentum}

For truck Q, the initial momentum is 0, and the final momentum can be calculated as:

pQ,extfinal=mQimesvQ=3000extkgimes9extms1=27000extkgm/sp_{Q, ext{final}} = m_Q imes v_Q = 3000 ext{ kg} imes 9 ext{ ms}^{-1} = 27000 ext{ kg m/s}

Thus, the impulse exerted by P on Q is:

I=27000extNsI = 27000 ext{ Ns}

Step 2

(b) the value of m.

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Answer

To find the mass m of truck P, we can use the principle of conservation of linear momentum. The total momentum before the collision must equal the total momentum after the collision:

extInitialmomentum=extFinalmomentum ext{Initial momentum} = ext{Final momentum}

The initial momentum is:

15mextkgm/s15m ext{ kg m/s}

And the final momentum, taking the directions into account, is:

3m+27000extkgm/s-3m + 27000 ext{ kg m/s}

Setting these equal gives:

15m=3m+2700015m = -3m + 27000

Solving for m:

15m+3m=2700015m + 3m = 27000 18m=2700018m = 27000 m=2700018=1500extkgm = \frac{27000}{18} = 1500 ext{ kg}

So, the mass of truck P is 1500 kg.

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