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A truck of mass 1750 kg is towing a car of mass 750 kg along a straight horizontal road - Edexcel - A-Level Maths Mechanics - Question 7 - 2013 - Paper 1

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A truck of mass 1750 kg is towing a car of mass 750 kg along a straight horizontal road. The two vehicles are joined by a light towbar which is inclined at an angle ... show full transcript

Worked Solution & Example Answer:A truck of mass 1750 kg is towing a car of mass 750 kg along a straight horizontal road - Edexcel - A-Level Maths Mechanics - Question 7 - 2013 - Paper 1

Step 1

Find the deceleration of the truck and the car.

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Answer

To find the deceleration of both the truck and the car, we can use the equation of motion:

v2=u2+2asv^2 = u^2 + 2a s

where:

  • Final velocity (vv) = 14 m s⁻¹
  • Initial velocity (uu) = 20 m s⁻¹
  • Distance (ss) = 100 m

Rearranging the equation:

142=202+2a(100)14^2 = 20^2 + 2a(100)

Calculating this:

196=400+200a196 = 400 + 200a 200a=196400200a = 196 - 400

ightarrow a = -1.02 ext{ m s}^{-2}$$ Thus, the deceleration of both the truck and car is 1.02 m s⁻².

Step 2

Find the force in the towbar.

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Answer

To calculate the force in the towbar, we need to analyze the horizontal forces acting on the car.

Using the equation:

T300500extcosθ=0T - 300 - 500 ext{cos}θ = 0

Substituting the given values (considering cos θ = 0.9):

T300500(0.9)=0T - 300 - 500(0.9) = 0 T300450=0T - 300 - 450 = 0 T=750extNT = 750 ext{ N}

Thus, the force in the towbar is 750 N.

Step 3

Find the value of R.

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Answer

Now, to find the value of R, we analyze the horizontal forces acting on the truck:

Using the equation:

800+R5001750=0800 + R - 500 - 1750 = 0

Giving, substituting values:

800+R5001750=0800 + R - 500 - 1750 = 0 R=1750800+500R = 1750 - 800 + 500 R=1450extNR = 1450 ext{ N}

Therefore, the value of R is 1450 N.

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