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Figure 3 shows a sketch of the circle C with centre N and equation $$(x - 2)^2 + (y + 1)^2 = \frac{169}{4}$$ (a) Write down the coordinates of N - Edexcel - A-Level Maths Pure - Question 9 - 2010 - Paper 4

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Figure-3-shows-a-sketch-of-the-circle-C-with-centre-N-and-equation--$$(x---2)^2-+-(y-+-1)^2-=-\frac{169}{4}$$--(a)-Write-down-the-coordinates-of-N-Edexcel-A-Level Maths Pure-Question 9-2010-Paper 4.png

Figure 3 shows a sketch of the circle C with centre N and equation $$(x - 2)^2 + (y + 1)^2 = \frac{169}{4}$$ (a) Write down the coordinates of N. (b) Find the rad... show full transcript

Worked Solution & Example Answer:Figure 3 shows a sketch of the circle C with centre N and equation $$(x - 2)^2 + (y + 1)^2 = \frac{169}{4}$$ (a) Write down the coordinates of N - Edexcel - A-Level Maths Pure - Question 9 - 2010 - Paper 4

Step 1

Write down the coordinates of N.

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Answer

The center N of the circle shown in Figure 3 is at the coordinates (2, -1).

Step 2

Find the radius of C.

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Answer

The radius can be found from the equation of the circle:

r=1694=132=6.5.r = \sqrt{\frac{169}{4}} = \frac{13}{2} = 6.5.

Step 3

Find the coordinates of A and the coordinates of B.

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Answer

Since chord AB is parallel to the x-axis and lies below the x-axis with a length of 12 units, we can set the coordinates as follows:

  1. Let the y-coordinate of points A and B be yA=yB=4y_A = y_B = -4.

  2. To find the x-coordinates:

    • For point A, xA=26=4x_A = 2 - 6 = -4.
    • For point B, xB=2+6=8x_B = 2 + 6 = 8.

Thus, the coordinates are A(-4, -4) and B(8, -4).

Step 4

Show that angle ANB = 134.8°, to the nearest 0.1 of a degree.

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Answer

Using the sine rule in triangle ANB, we have:

sin(ANB)=oppositehypotenuse=66.5.\sin(\angle ANB) = \frac{\text{opposite}}{\text{hypotenuse}} = \frac{6}{6.5}.

Calculating gives:

ANB=arcsin(66.5)=67.3°.\angle ANB = \arcsin\left(\frac{6}{6.5}\right) = 67.3°.
Since we know the triangle's angle sum property, we can calculate:

ANB=180°2×67.3°=134.8°.\angle ANB = 180° - 2 \times 67.3° = 134.8°.

Step 5

Find the length AP, giving your answer to 3 significant figures.

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Answer

Using triangle ANP:

AP=6.5sin(67.4°)AP = 6.5 \cdot \sin(67.4°) gives:

AP15.6.AP \approx 15.6.
Thus, the length of AP rounded to 3 significant figures is approximately 15.6.

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