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Question 4
Given y = 3√(x - 6x + 4), x > 0 (a) find ∫ y dx, simplifying each term. (b) (i) Find dy/dx (ii) Hence find the value of x such that dy/dx = 0.
Step 1
Answer
To evaluate the integral of y, first rewrite y clearly:
Now compute the integral:
To perform the integration, let's use substitution:
Let ( u = 4 - 6x ) Then, ( du = -6 , dx \rightarrow dx = -\frac{1}{6}du )
Substituting gives:
Now, integrating:
Substituting back for u:
The final result of the integral is:
Step 2
Step 3
Answer
Setting the derivative ( \frac{dy}{dx} ) equal to 0:
The above equation does not yield any real value for x since a square root cannot equal zero in the denominator. Therefore, it cannot be solved by setting ( \frac{dy}{dx} = 0 ). This indicates that there are no critical points where the slope/fall of the curve y is flat. However, if you set the numerator conditionally (i.e., 9 = 0), it holds no real solution. The function has no horizontal tangents; thus, no value of x exists such that ( \frac{dy}{dx} = 0 ).
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