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The amount of an antibiotic in the bloodstream, from a given dose, is modelled by the formula $$x = D e^{-0.2t}$$ where $x$ is the amount of the antibiotic in the bloodstream in milligrams, $D$ is the dose given in milligrams and $t$ is the time in hours after the antibiotic has been given - Edexcel - A-Level Maths Pure - Question 1 - 2015 - Paper 3

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Question 1

The-amount-of-an-antibiotic-in-the-bloodstream,-from-a-given-dose,-is-modelled-by-the-formula--$$x-=-D-e^{-0.2t}$$--where-$x$-is-the-amount-of-the-antibiotic-in-the-bloodstream-in-milligrams,-$D$-is-the-dose-given-in-milligrams-and-$t$-is-the-time-in-hours-after-the-antibiotic-has-been-given-Edexcel-A-Level Maths Pure-Question 1-2015-Paper 3.png

The amount of an antibiotic in the bloodstream, from a given dose, is modelled by the formula $$x = D e^{-0.2t}$$ where $x$ is the amount of the antibiotic in the ... show full transcript

Worked Solution & Example Answer:The amount of an antibiotic in the bloodstream, from a given dose, is modelled by the formula $$x = D e^{-0.2t}$$ where $x$ is the amount of the antibiotic in the bloodstream in milligrams, $D$ is the dose given in milligrams and $t$ is the time in hours after the antibiotic has been given - Edexcel - A-Level Maths Pure - Question 1 - 2015 - Paper 3

Step 1

Use the model to find the amount of the antibiotic in the bloodstream 4 hours after the dose is given.

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Answer

To find the amount of antibiotic after 4 hours, we substitute the values into the model:

D=15, t=4D = 15, \ t = 4

Then we calculate:

x=15e0.2×4x = 15 e^{-0.2 \times 4} =15e0.8= 15 e^{-0.8}

Calculating e0.80.4493e^{-0.8} \approx 0.4493, we find:

x15×0.44936.740x \approx 15 \times 0.4493 \approx 6.740

Thus, the amount of antibiotic in the bloodstream after 4 hours is approximately 6.740 mg.

Step 2

Show that the total amount of the antibiotic in the bloodstream 2 hours after the second dose is given is 13.754 mg.

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Answer

After administering the second dose at t=5t = 5 hours, we need to find the amount at t=7t = 7 hours:

For the first dose: x1=15e0.2×7x_1 = 15 e^{-0.2 \times 7} For the second dose administered after 5 hours: x2=15e0.2×(75)=15e0.4x_2 = 15 e^{-0.2 \times (7 - 5)} = 15 e^{-0.4}

Calculating:

x115e1.415×0.24663.699x_1 \approx 15 e^{-1.4}\approx 15 \times 0.2466 \approx 3.699

x215e0.415×0.670310.055x_2 \approx 15 e^{-0.4} \approx 15 \times 0.6703 \approx 10.055

Total amount: x1+x23.699+10.05513.754x_1 + x_2 \approx 3.699 + 10.055 \approx 13.754

Thus, the total amount of the antibiotic in the bloodstream 2 hours after the second dose is 13.754 mg.

Step 3

Show that $T = a \ln \left( \frac{b + b}{e} \right)$, where $a$ and $b$ are integers to be determined.

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Answer

Given at time t=7t = 7 hours, the total antibiotic amount is 7.5 mg:

Substituting into the total amount formula:

15e0.2×7+15e0.2×(75)=7.515 e^{-0.2 \times 7} + 15 e^{-0.2 \times (7 - 5)} = 7.5

This leads to:

7.5=15e1.4+15e0.47.5 = 15 e^{-1.4} + 15 e^{-0.4}

Dividing both sides by 15 gives:

7.515=e1.4+e0.4\frac{7.5}{15} = e^{-1.4} + e^{-0.4}

This can be rearranged to determine TT, finding the integers aa and bb. The calculations will lead to identifying the values for aa and bb.

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