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Solve (a) $s^5 = 8$, giving your answer to 3 significant figures, (b) $ ext{log}_2 (x + 1) - ext{log}_2 x = ext{log}_2 7.$ - Edexcel - A-Level Maths Pure - Question 4 - 2005 - Paper 2

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Solve--(a)-$s^5-=-8$,-giving-your-answer-to-3-significant-figures,--(b)-$-ext{log}_2-(x-+-1)----ext{log}_2-x-=--ext{log}_2-7.$-Edexcel-A-Level Maths Pure-Question 4-2005-Paper 2.png

Solve (a) $s^5 = 8$, giving your answer to 3 significant figures, (b) $ ext{log}_2 (x + 1) - ext{log}_2 x = ext{log}_2 7.$

Worked Solution & Example Answer:Solve (a) $s^5 = 8$, giving your answer to 3 significant figures, (b) $ ext{log}_2 (x + 1) - ext{log}_2 x = ext{log}_2 7.$ - Edexcel - A-Level Maths Pure - Question 4 - 2005 - Paper 2

Step 1

(a) $s^5 = 8$, giving your answer to 3 significant figures

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Answer

To solve for ss, we can rewrite the equation as:

s=81/5s = 8^{1/5}

Calculating this gives:

s=2.0s = 2.0

So the final answer, expressed to three significant figures, is:

s=2.00s = 2.00

Step 2

(b) log2 (x + 1) - log2 x = log2 7.

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104 rated

Answer

Using the properties of logarithms, we can combine the left side:

extlog2(x+1x)=log27 ext{log}_2 \left( \frac{x + 1}{x} \right) = \text{log}_2 7

This implies:

x+1x=7\frac{x + 1}{x} = 7

Multiplying both sides by xx results in:

x+1=7xx + 1 = 7x

Rearranging gives:

1=6x1 = 6x

Finally, we solve for xx:

x=16(which is approximately 0.167)x = \frac{1}{6} \\ \text{(which is approximately 0.167)}

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