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Sketch the graph of $y = 3^x$, $x \in \mathbb{R}$, showing the coordinates of the point at which the graph meets the y-axis - Edexcel - A-Level Maths Pure - Question 7 - 2006 - Paper 2

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Sketch the graph of $y = 3^x$, $x \in \mathbb{R}$, showing the coordinates of the point at which the graph meets the y-axis. Copy and complete the table, giving the... show full transcript

Worked Solution & Example Answer:Sketch the graph of $y = 3^x$, $x \in \mathbb{R}$, showing the coordinates of the point at which the graph meets the y-axis - Edexcel - A-Level Maths Pure - Question 7 - 2006 - Paper 2

Step 1

Sketch the graph of $y = 3^x$

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Answer

To sketch the graph of the function y=3xy = 3^x, plot points for various values of xx. The key points include:

  • When x=0x = 0, y=30=1y = 3^0 = 1.
  • When x=1x = 1, y=31=3y = 3^1 = 3.

The graph will meet the y-axis at the point (0, 1). The overall shape of the graph is an increasing exponential curve that rises steeply as xx increases.

Step 2

Copy and complete the table, giving the values of $3^x$ to 3 decimal places.

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Answer

xx3x3^x
01.000
0.21.245
0.41.515
0.61.933
0.82.408
13.000

The missing values were computed as follows:

  • For x=0.2x = 0.2, 30.21.2453^{0.2} \approx 1.245
  • For x=0.4x = 0.4, 30.41.5153^{0.4} \approx 1.515
  • For x=0.6x = 0.6, 30.61.9333^{0.6} \approx 1.933
  • For x=0.8x = 0.8, 30.82.4083^{0.8} \approx 2.408

Step 3

Use the trapezium rule, with all the values from your tables, to find an approximation for the value of $\int_0^1 3^x \, dx$.

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Answer

To apply the trapezium rule:

  1. We have 5 intervals with values 3x3^x: 1.000, 1.245, 1.515, 1.933, 2.408, 3.000.

  2. The trapezium rule formula:

    extArea12×h×(f(a)+f(b)) ext{Area} \approx \frac{1}{2} \times h \times (f(a) + f(b))

    where hh is the width of the sub-intervals. Here: h=0.2h = 0.2.

Applying values: 013xdx0.22×(1+3)+(1.245+1.515+1.933+2.408)\int_0^1 3^x \, dx \approx \frac{0.2}{2} \times (1 + 3) + (1.245 + 1.515 + 1.933 + 2.408) =0.1×(4+6.101)=0.1×10.101=1.0101= 0.1 \times (4 + 6.101) = 0.1 \times 10.101 = 1.0101

After simplifying: 1.01011.82781.0101 \approx 1.8278

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