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6. (a) Find, to 3 significant figures, the value of x for which 8^x = 0.8 - Edexcel - A-Level Maths Pure - Question 7 - 2007 - Paper 2

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6. (a) Find, to 3 significant figures, the value of x for which 8^x = 0.8. (b) Solve the equation 2 log_1 x - log_1 7x = 1.

Worked Solution & Example Answer:6. (a) Find, to 3 significant figures, the value of x for which 8^x = 0.8 - Edexcel - A-Level Maths Pure - Question 7 - 2007 - Paper 2

Step 1

Find, to 3 significant figures, the value of x for which 8^x = 0.8.

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Answer

To solve the equation, we first take the logarithm of both sides:

egin{align*} 8^x &= 0.8 \\ ext{Taking log base 10:} \\ ext{log}(8^x) &= ext{log}(0.8) \\ ext{This simplifies to:} \\ x imes ext{log}(8) &= ext{log}(0.8) \\ x &= \frac{ ext{log}(0.8)}{ ext{log}(8)} ext{Using a calculator, we find:} \\ x \approx -0.107. \end{align*}

The value of x, rounded to three significant figures, is -0.107.

Step 2

Solve the equation 2 log_1 x - log_1 7x = 1.

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Answer

We start with the equation:

2extlog1xextlog1(7x)=1.2 ext{log}_1 x - ext{log}_1 (7x) = 1.

Using the properties of logarithms, we can rewrite the second term:

extlog1(7x)=extlog17+extlog1x. ext{log}_1 (7x) = ext{log}_1 7 + ext{log}_1 x.

Substituting this back into the equation, we have:

2extlog1x(extlog17+extlog1x)=1.2 ext{log}_1 x - ( ext{log}_1 7 + ext{log}_1 x) = 1.

This simplifies to:

extlog1x=1+extlog17. ext{log}_1 x = 1 + ext{log}_1 7.

Now, we can rearrange and exponentiate:

extlog1x=extlog1(7imes101)=extlog170. ext{log}_1 x = ext{log}_1 (7 imes 10^1) = ext{log}_1 70.

Thus, we find:

x=70.x = 70.

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