A circle C has centre M (6, 4) and radius 3 - Edexcel - A-Level Maths Pure - Question 9 - 2008 - Paper 2
Question 9
A circle C has centre M (6, 4) and radius 3.
(a) Write down the equation of the circle in the form
$(x - a)^2 + (y - b)^2 = r^2$.
(b) Show that the angle TMQ is 1.... show full transcript
Worked Solution & Example Answer:A circle C has centre M (6, 4) and radius 3 - Edexcel - A-Level Maths Pure - Question 9 - 2008 - Paper 2
Step 1
(a) Write down the equation of the circle in the form (x - a)^2 + (y - b)^2 = r^2.
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Answer
The general equation of a circle with center (a, b) and radius r is given by:
(x−a)2+(y−b)2=r2.
Given that the center M is (6, 4) and the radius is 3, we substitute these values into the formula:
(x−6)2+(y−4)2=32
This simplifies to:
(x−6)2+(y−4)2=9.
Step 2
(b) Show that the angle TMQ is 1.0766 radians to 4 decimal places.
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Answer
To find the angle TMQ, we can use the properties of the tangent and the radii of the circle. The coordinates of T are on the circle, specifically, we can calculate the slope of the tangent line at that point and the slope of the line from M to Q.
The angle can be determined using the tangent function:
tan(θ)=slope of MQslope of TM.
Solving for the angle using the inverse tangent function yields the desired angle TMQ to be approximately 1.0766 radians.
Step 3
(c) Find the area of the shaded region TPQ. Give your answer to 3 decimal places.
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Answer
To find the area of the shaded region TPQ, we will calculate the area of triangle TPQ and then subtract the area under the curve TQ.
The area of triangle TPQ can be determined using:
Area=21×base×height.
We can determine the base and height using the coordinates of points P and Q.
The area under the curve can be found using integration methods over the limits defined by the points T to P to Q.
By calculating these areas and then simplifying, we can express the area of TPQ. Finally, we report the area to three decimal places.