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Figure 1 shows a sketch of a curve C with equation $y = f(x)$ where $f(x)$ is a cubic expression in $x$ - Edexcel - A-Level Maths Pure - Question 8 - 2022 - Paper 1

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Figure-1-shows-a-sketch-of-a-curve-C-with-equation-$y-=-f(x)$-where-$f(x)$-is-a-cubic-expression-in-$x$-Edexcel-A-Level Maths Pure-Question 8-2022-Paper 1.png

Figure 1 shows a sketch of a curve C with equation $y = f(x)$ where $f(x)$ is a cubic expression in $x$. The curve - passes through the origin - has a maximum ... show full transcript

Worked Solution & Example Answer:Figure 1 shows a sketch of a curve C with equation $y = f(x)$ where $f(x)$ is a cubic expression in $x$ - Edexcel - A-Level Maths Pure - Question 8 - 2022 - Paper 1

Step 1

Write down the set of values of $x$ for which $f'(x) < 0$

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Answer

The function f(x)f'(x) represents the gradient of the curve. Given the graph, it is visible that the curve is decreasing between the points (2,8)(2, 8) and (6,0)(6, 0), so we conclude that the values of xx for which f(x)<0f'(x) < 0 are:
2<x<62 < x < 6

Step 2

Find the set of values of $k$, giving your answer in set notation

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Answer

From the behavior of the cubic function and the horizontal line test, the line y=ky = k intersects the curve C at only one point when kk is greater than the local maximum value at (2,8)(2, 8) or less than the local minimum value at (6,0)(6, 0). Therefore, we can state the set of values of kk as:
ext{{{k | k > 8}}} igcup ext{{{k | k < 0}}}

Step 3

Find the equation of C. You may leave your answer in factorised form

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Answer

To find the equation of the cubic curve C, we can use the turning points. Let CC be y=a(xr1)(xr2)(xr3)y = a(x - r_1)(x - r_2)(x - r_3). Using the given points, we can assume it is of the form:
y=a(x)(x2)(x6)y = a(x)(x - 2)(x - 6)
To find aa, we substitute one of the given points, such as (2,8)(2, 8), into the function. After some calculations, we arrive at:
C: y = rac{1}{4}x(x - 2)(x - 6)
Thus, the factorised equation of C is:
y = rac{1}{4}x(x - 2)(x - 6)

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