Photo AI

The curve C has equation $y = \frac{1}{3}x^2 + 8$ - Edexcel - A-Level Maths Pure - Question 11 - 2014 - Paper 2

Question icon

Question 11

The-curve-C-has-equation-$y-=-\frac{1}{3}x^2-+-8$-Edexcel-A-Level Maths Pure-Question 11-2014-Paper 2.png

The curve C has equation $y = \frac{1}{3}x^2 + 8$. The line L has equation $y = 3x + k$, where $k$ is a positive constant. (a) Sketch C and L on separate diagrams,... show full transcript

Worked Solution & Example Answer:The curve C has equation $y = \frac{1}{3}x^2 + 8$ - Edexcel - A-Level Maths Pure - Question 11 - 2014 - Paper 2

Step 1

Sketch C and L on separate diagrams

96%

114 rated

Answer

To sketch the curve C, we start by plotting the vertex at the point (0, 8) since the vertex form for the parabola is y=13x2+8y = \frac{1}{3}x^2 + 8.

  1. Identify the intercepts for C:

    • The y-intercept occurs when x=0x = 0:
      • y=13(0)2+8=8y = \frac{1}{3}(0)^2 + 8 = 8, hence (0,8)(0, 8).
    • The x-intercepts are found by setting y=0y = 0:
      • Solve 0=13x2+80 = \frac{1}{3}x^2 + 8, which gives no real x-intercepts because 88 is positive.
  2. Shape of C:

    • The graph is an upward-opening parabola, symmetric about the y-axis.
  3. Sketch line L:

    • For the line y=3x+ky = 3x + k, it will also cross the y-axis at the point (0,k)(0, k).
    • The slope is positive, indicating the line will rise as x increases.
  4. Identify points of intersection:

    • Line L will cut the y-axis at (0,k)(0, k), and its x-intercept can be found by setting y=0y = 0:
      • 0=3x+kx=k30 = 3x + k \Rightarrow x = -\frac{k}{3}, hence the intercept (k3,0)( -\frac{k}{3}, 0).

Step 2

find the value of k

99%

104 rated

Answer

Since line L is tangent to curve C, at the point of tangency, both the y-values and the slopes of the two equations must be equal.

  1. Equate curves:
    • Set the equations equal: 13x2+8=3x+k\frac{1}{3}x^2 + 8 = 3x + k
    • Rearranging gives: 13x23x+(8k)=0\frac{1}{3}x^2 - 3x + (8 - k) = 0
  2. Condition for tangency:
    • For tangency, the discriminant must be zero: b24ac=0b^2 - 4ac = 0
    • Here, a=13,b=3, and c=(8k)a = \frac{1}{3}, b = -3, \text{ and } c = (8 - k).
    • Calculate the discriminant: (3)24(13)(8k)=0(-3)^2 - 4 \left( \frac{1}{3} \right)(8 - k) = 0
    • Solving the equation gives: 943(8k)=09 - \frac{4}{3}(8 - k) = 0 9=324k39 = \frac{32 - 4k}{3} 27=324k27 = 32 - 4k 4k=3227=5k=544k = 32 - 27 = 5\Rightarrow k = \frac{5}{4} Thus, the value of k is (1.25).

Join the A-Level students using SimpleStudy...

97% of Students

Report Improved Results

98% of Students

Recommend to friends

100,000+

Students Supported

1 Million+

Questions answered

;