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Figure 3 shows a sketch of part of the curve C with equation y = 3^x The point P lies on C and has coordinates (2, 9) - Edexcel - A-Level Maths Pure - Question 1 - 2014 - Paper 4

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Question 1

Figure-3-shows-a-sketch-of-part-of-the-curve-C-with-equation--y-=-3^x--The-point-P-lies-on-C-and-has-coordinates-(2,-9)-Edexcel-A-Level Maths Pure-Question 1-2014-Paper 4.png

Figure 3 shows a sketch of part of the curve C with equation y = 3^x The point P lies on C and has coordinates (2, 9). The line l is a tangent to C at P. The line... show full transcript

Worked Solution & Example Answer:Figure 3 shows a sketch of part of the curve C with equation y = 3^x The point P lies on C and has coordinates (2, 9) - Edexcel - A-Level Maths Pure - Question 1 - 2014 - Paper 4

Step 1

Find the exact value of the x coordinate of Q.

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Answer

To find the x-coordinate of point Q, we first need to determine the equation of the tangent line l at point P (2, 9). The derivative of the curve ( y = 3^x ) with respect to x is:

dydx=3xln(3)\frac{dy}{dx} = 3^x \ln(3)

Evaluating this derivative at x = 2 gives:

dydxx=2=32ln(3)=9ln(3)\frac{dy}{dx}\bigg|_{x=2} = 3^2 \ln(3) = 9 \ln(3)

The equation of the tangent line at point P can be formulated using the point-slope form:

y9=9ln(3)(x2)y - 9 = 9 \ln(3)(x - 2)

To find where this line intersects the x-axis (i.e., where y = 0), substitute y = 0:

09=9ln(3)(x2)0 - 9 = 9 \ln(3)(x - 2)

Solving for x:

9=9ln(3)(x2)-9 = 9 \ln(3)(x - 2)

x2=99ln(3)x - 2 = \frac{-9}{9 \ln(3)}

x=21ln(3)x = 2 - \frac{1}{\ln(3)}

Thus, the exact value of the x-coordinate of Q is:

xQ=21ln(3).x_Q = 2 - \frac{1}{\ln(3)}.

Step 2

Use integration to find the exact value of the volume of the solid generated.

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Answer

The volume V of the solid formed by rotating region R about the x-axis can be calculated using the disk method:

V=π0xQ(3x)2dxV = \pi \int_{0}^{x_Q} (3^x)^2 \, dx

This simplifies to:

V=π0xQ9xdxV = \pi \int_{0}^{x_Q} 9^{x} \, dx

The integral of ( 9^x ) is:

9xdx=9xln(9)+C\int 9^x \, dx = \frac{9^x}{\ln(9)} + C

Thus, evaluating the definite integral:

V=π[9xln(9)]0xQV = \pi \left[ \frac{9^x}{\ln(9)} \right]_{0}^{x_Q}

Substituting the limits:

V=π(9xQln(9)90ln(9))V = \pi \left( \frac{9^{x_Q}}{\ln(9)} - \frac{9^{0}}{\ln(9)} \right)

Simplifying further:

V=π(921ln(3)ln(9)1ln(9))=πln(9)(921ln(3)1)V = \pi \left( \frac{9^{2 - \frac{1}{\ln(3)}}}{\ln(9)} - \frac{1}{\ln(9)} \right) = \frac{\pi}{\ln(9)} \left( 9^{2 - \frac{1}{\ln(3)}} - 1 \right)

Thus, the volume of the solid generated is:

V=pqV = \frac{p}{q}

where p and q can be determined based on the expression derived.

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