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Question 6
Given that $y = 2$ at $x = \frac{\pi}{4}$, solve the differential equation $$\frac{dy}{dx} = \frac{3}{y \cos x}$$
Step 1
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Answer
To solve the differential equation, we first rewrite it in a separable form:
y dy=3 sec2x dxy \, dy = 3 \, sec^2 x \, dxydy=3sec2xdx
Now, we integrate both sides:
∫y dy=∫3 sec2x dx\int y \, dy = \int 3 \, sec^2 x \, dx∫ydy=∫3sec2xdx
This gives:
12y2=3tanx+C\frac{1}{2} y^2 = 3 \tan x + C21y2=3tanx+C
Step 2
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At x=π4x = \frac{\pi}{4}x=4π, y=2y = 2y=2. We substitute these values into the equation:
12(2)2=3tan(π4)+C\frac{1}{2} (2)^2 = 3 \tan \left( \frac{\pi}{4} \right) + C21(2)2=3tan(4π)+C
This simplifies to:
2=3(1)+C2 = 3(1) + C2=3(1)+C
Thus,
C=2−3=−1C = 2 - 3 = -1C=2−3=−1
Step 3
101 rated
Substituting back the value of CCC into the integrated equation, we have:
12y2=3tanx−1\frac{1}{2} y^2 = 3 \tan x - 121y2=3tanx−1
To write this in a standard form:
y2=6tanx−2y^2 = 6 \tan x - 2y2=6tanx−2
This is the solution to the differential equation.
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