f(x) = x² - 8x + 19
(a) Express f(x) in the form (x + a)² + b, where a and b are constants - Edexcel - A-Level Maths Pure - Question 7 - 2017 - Paper 1
Question 7
f(x) = x² - 8x + 19
(a) Express f(x) in the form (x + a)² + b, where a and b are constants.
The curve C with equation y = f(x) crosses the y-axis at the point P a... show full transcript
Worked Solution & Example Answer:f(x) = x² - 8x + 19
(a) Express f(x) in the form (x + a)² + b, where a and b are constants - Edexcel - A-Level Maths Pure - Question 7 - 2017 - Paper 1
Step 1
Express f(x) in the form (x + a)² + b
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Answer
To express the quadratic function in the form (x + a)² + b, we can complete the square.
Start with the given function:
f(x)=x2−8x+19
To complete the square for the expression x2−8x, take half of the coefficient of x, which is −4, and square it to get 16.
Rewrite the function:
f(x)=(x2−8x+16)+19−16
This results in:
f(x)=(x−4)2+3
Thus, we have a=−4 and b=3.
Step 2
Sketch the graph of C showing the coordinates of point P and the coordinates of point Q
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Answer
The curve C is a parabola that opens upwards, with its vertex representing the minimum point Q.
The coordinates of point P, where the curve crosses the y-axis, can be found by evaluating f(0):
f(0)=(0−4)2+3=16+3=19
Therefore, P(0, 19).
The coordinates of point Q, which is the vertex, are (4, 3).
When sketching the graph, ensure to mark:
Point P at (0, 19)
Point Q at (4, 3)
The graph should be a U-shaped curve that is symmetrical about the vertical line x = 4.
Step 3
Find the distance PQ, writing your answer as a simplified surd
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Answer
To find the distance between points P(0, 19) and Q(4, 3), we can use the distance formula:
d = ext{PQ} = rac{ ext{distance between } P ext{ and } Q}{ ext{distance formula}}