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Find the exact solutions to the equations (a) ln x + ln 3 = ln 6, (b) e^x + 3e^{x} = 4. - Edexcel - A-Level Maths Pure - Question 3 - 2007 - Paper 5

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Find-the-exact-solutions-to-the-equations-(a)-ln-x-+-ln-3-=-ln-6,-(b)-e^x-+-3e^{x}-=-4.-Edexcel-A-Level Maths Pure-Question 3-2007-Paper 5.png

Find the exact solutions to the equations (a) ln x + ln 3 = ln 6, (b) e^x + 3e^{x} = 4.

Worked Solution & Example Answer:Find the exact solutions to the equations (a) ln x + ln 3 = ln 6, (b) e^x + 3e^{x} = 4. - Edexcel - A-Level Maths Pure - Question 3 - 2007 - Paper 5

Step 1

(a) ln x + ln 3 = ln 6

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Answer

To solve the equation, we use the property of logarithms that states: ( \ln a + \ln b = \ln(ab)). Thus, we can rewrite the left side as:

ln(x3)=ln(6)\ln(x \cdot 3) = \ln(6)

This leads to:

3x=6.3x = 6.

Dividing both sides by 3 gives:

x=2.x = 2.

This is the exact solution for part (a).

Step 2

(b) e^x + 3e^{x} = 4

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Answer

First, we can combine the terms on the left:

4ex=4.4e^x = 4.

Dividing both sides by 4 results in:

ex=1.e^x = 1.

Taking the natural logarithm of both sides:

x=ln(1)=0.x = \ln(1) = 0.

Thus, the exact solution for part (b) is:

x=0.x = 0.

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