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Figure 1 shows the plan of a garden - Edexcel - A-Level Maths Pure - Question 8 - 2014 - Paper 2

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Question 8

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Figure 1 shows the plan of a garden. The marked angles are right angles. The six edges are straight lines. The lengths shown in the diagram are given in metres. G... show full transcript

Worked Solution & Example Answer:Figure 1 shows the plan of a garden - Edexcel - A-Level Maths Pure - Question 8 - 2014 - Paper 2

Step 1

show that $x > 1.7$

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Answer

To find the perimeter of the garden, we can set up the equation based on the lengths provided in the diagram:

P=20x+6P = 20x + 6

From the question, we know that the perimeter must be greater than 40 meters:

20x+6>4020x + 6 > 40

Solving for xx:

20x>40620x > 40 - 6
20x>3420x > 34
x > rac{34}{20}
x>1.7x > 1.7

Step 2

form and solve a quadratic inequality in $x$

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Answer

The area AA of the garden can be expressed as:

A=2x(6x+3)+4x(4x)2x(4x+3)A = 2x(6x + 3) + 4x(4x) - 2x(4x + 3)
A=2x(6x+3)+16x22x(4x+3)A = 2x(6x + 3) + 16x^2 - 2x(4x + 3)
A=12x2+6x+16x28x6xA = 12x^2 + 6x + 16x^2 - 8x - 6x
A=28x26xA = 28x^2 - 6x

Given that the area must be less than 120 m2^2:

28x26x<12028x^2 - 6x < 120
28x26x120<028x^2 - 6x - 120 < 0

Next, we solve the quadratic inequality:

Using the quadratic formula: x = rac{-b ext{±} ext{sqrt}(b^2 - 4ac)}{2a} where a=28a = 28, b=6b = -6, and c=120c = -120.

Calculating the discriminant: b24ac=(6)24(28)(120)=36+13440=13476b^2 - 4ac = (-6)^2 - 4(28)(-120) = 36 + 13440 = 13476

Finding the roots: x = rac{6 ext{±} ext{sqrt}(13476)}{56} This gives us the critical values needed to determine the intervals for the quadratic inequality.

Step 3

Hence state the range of the possible values of $x$

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Answer

After solving the inequality and evaluating the intervals, we express the final range of xx:

1.7 < x < rac{5}{2}
This implies that the permissible values for xx lie within the interval (1.7,2.5)(1.7, 2.5), confirming both conditions provided in the question.

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