7. (i) Find the exact value of x for which
$$
\log_2(2x) = \log_2(5x + 4) - 3
$$
(ii) Given that
$$
\log_y y + 3\log_2 2 = 5
$$
express y in terms of a - Edexcel - A-Level Maths Pure - Question 9 - 2013 - Paper 4
Question 9
7. (i) Find the exact value of x for which
$$
\log_2(2x) = \log_2(5x + 4) - 3
$$
(ii) Given that
$$
\log_y y + 3\log_2 2 = 5
$$
express y in terms of a.
Give y... show full transcript
Worked Solution & Example Answer:7. (i) Find the exact value of x for which
$$
\log_2(2x) = \log_2(5x + 4) - 3
$$
(ii) Given that
$$
\log_y y + 3\log_2 2 = 5
$$
express y in terms of a - Edexcel - A-Level Maths Pure - Question 9 - 2013 - Paper 4
Step 1
Find the exact value of x for which
$$
\log_2(2x) = \log_2(5x + 4) - 3
$$
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114 rated
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Answer
To solve for x, start by applying the properties of logarithms:
Rewrite the equation:
log2(2x)=log2(5x+4)−3
Move the logarithmic term to one side:
log2(2x)+3=log2(5x+4)
Rewrite 3 in terms of logarithms:
log2(2x)+log2(23)=log2(5x+4)
Combine the logarithms:
log2(2x⋅8)=log2(5x+4)
which simplifies to:
log2(16x)=log2(5x+4)
Set the arguments of the logarithms equal:
16x=5x+4
Solve for x:
16x−5x=4 11x=4 x=114
Step 2
Given that
$$
\log_y y + 3\log_2 2 = 5
$$
express y in terms of a.
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Answer
Simplify the logarithmic expression:
Since logyy=1, we can replace it:
1+3log22=5
Recall that log22=1:
1+3⋅1=5
simplifies to:
1+3=5
This means we need to express y in terms of another variable a:
To isolate y, we can use:
3+1=5 implies y must follow y=ak format for some base a. Depending on the context of the problem,
you can express y in the simplest terms as:
y=25−3=22=4.