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Figure 1 shows a sketch of the curve with equation $y = f(x)$ - Edexcel - A-Level Maths Pure - Question 8 - 2010 - Paper 1

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Question 8

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Figure 1 shows a sketch of the curve with equation $y = f(x)$. The curve has a maximum point A at $(-2, 3)$ and a minimum point B at $(3, -5)$. On separate diagram... show full transcript

Worked Solution & Example Answer:Figure 1 shows a sketch of the curve with equation $y = f(x)$ - Edexcel - A-Level Maths Pure - Question 8 - 2010 - Paper 1

Step 1

a) $y = f(x + 3)$

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Answer

To sketch the graph of y=f(x+3)y = f(x + 3), we will perform a horizontal translation to the left by 3 units.

  • The maximum point A, originally at (2,3)(-2, 3), will now move to (5,3)(-5, 3).
  • The minimum point B, originally at (3,5)(3, -5), will shift to (0,5)(0, -5).

Thus, the new coordinates marked on the sketch are:

  • Maximum A at (5,3)(-5, 3)
  • Minimum B at (0,5)(0, -5)

Label the coordinates on the graph.

Step 2

b) $y = 2f(x)$

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Answer

For the graph of y=2f(x)y = 2f(x), we will perform a vertical stretch of the graph by a factor of 2.

  • The maximum point A will now be at (2,2imes3)=(2,6)(-2, 2 imes 3) = (-2, 6).
  • The minimum point B will now be at (3,2imes5)=(3,10)(3, 2 imes -5) = (3, -10).

Label these coordinates on the graph as:

  • Maximum A at (2,6)(-2, 6)
  • Minimum B at (3,10)(3, -10).

Step 3

c) Write down the value of a.

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Answer

To find the value of aa in the equation y=f(x)+ay = f(x) + a, we know that this graph has a minimum at (3,0)(3, 0).

Since the minimum of f(x)f(x) is 5-5 at x=3x = 3, we set up the equation:

0=5+a0 = -5 + a

Solving for aa, we get:

a=5a = 5

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