Figure 1 shows part of the curve with equation $y = \sqrt{\tan x}$ - Edexcel - A-Level Maths Pure - Question 2 - 2007 - Paper 8
Question 2
Figure 1 shows part of the curve with equation $y = \sqrt{\tan x}$. The finite region $\mathcal{R}$, which is bounded by the curve, the x-axis and the line $x = \fra... show full transcript
Worked Solution & Example Answer:Figure 1 shows part of the curve with equation $y = \sqrt{\tan x}$ - Edexcel - A-Level Maths Pure - Question 2 - 2007 - Paper 8
Step 1
Given that $y = \sqrt{\tan x}$, complete the table with the values of $y$ corresponding to $x = 0, \frac{\pi}{16}, \frac{\pi}{8}$ and $\frac{3\pi}{16}$, giving your answers to 5 decimal places.
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Answer
x
0
16π
8π
163π
y
0
0.44600
0.64350
0.81742
Step 2
Use the trapezium rule with all the values of $y$ in the completed table to obtain an estimate for the area of the shaded region $R$, giving your answer to 4 decimal places.
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Answer
To apply the trapezium rule, we first calculate the area using the formula:
Area=21(b1+b2)h
First, we calculate the widths:
h=16π
b1=0.44600, b2=0.64350, b3=0.81742, and we sum the bases:
Area=32π(0+2(0.44600+0.64350+0.81742))
Calculating that gives:
Area = ≈0.4726 rounded to 4 decimal places.
Step 3
Use integration to find an exact value for the volume of the solid generated.
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Answer
To find the volume of the solid generated by rotating the region R around the x-axis, we use: