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Question 3
Given $y = 2x(3x - 1)^5$, (a) find \( \frac{dy}{dx} \), giving your answer as a single fully factorised expression. (b) Hence find the set of values of \( x \) ... show full transcript
Step 1
Answer
To find ( \frac{dy}{dx} ), we will apply the product rule of differentiation. Let ( u = 2x ) and ( v = (3x - 1)^5 ). The product rule states that:
First, we compute ( u' ) and ( v' ):
Now substituting back into the product rule:
Factoring out the common term ( (3x - 1)^4 ):
This simplifies to:
Thus, the final answer is:
Step 2
Answer
To find the set of values for which ( \frac{dy}{dx} \leq 0 ), we analyze the expression:
The factor ( 2(3x - 1)^4 ) is always non-negative since it is raised to an even power and multiplied by a positive constant. Thus, the sign of ( \frac{dy}{dx} ) is determined solely by ( 16x - 1 ).
Setting ( 16x - 1 \leq 0 ) gives:
Thus, the set of values of ( x ) for which ( \frac{dy}{dx} \leq 0 ) is:
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