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Question 8
6. (a) Write \( \sqrt{80} \) in the form \( c \sqrt{5} \), where \( c \) is a positive constant. (b) A rectangle R has a length of \( (1 + \sqrt{5}) \) cm and an ar... show full transcript
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Given that the length of rectangle R is ( (1 + \sqrt{5}) ) cm and the area is ( \sqrt{80} ) cm², we need to find the width ( w ).
The area can be expressed as:
[ \text{Area} = \text{Length} \times \text{Width} \implies \sqrt{80} = (1 + \sqrt{5}) w ]
To find ( w ), rewrite the equation:
[ w = \frac{\sqrt{80}}{1 + \sqrt{5}} ]
Next, we rationalize the denominator:
[ w = \frac{\sqrt{80}}{1 + \sqrt{5}} \cdot \frac{1 - \sqrt{5}}{1 - \sqrt{5}} = \frac{\sqrt{80}(1 - \sqrt{5})}{1 - 5} = \frac{\sqrt{80}(1 - \sqrt{5})}{-4} ]
We know that ( \sqrt{80} = 4\sqrt{5} ), so substituting this value gives:
[ w = \frac{4\sqrt{5}(1 - \sqrt{5})}{-4} = -\sqrt{5}(1 - \sqrt{5}) ]
This simplifies to:
[ w = -\sqrt{5} + 5 = 5 - \sqrt{5} ]
Thus, in the form ( p + q\sqrt{5} ), we have ( p = 5 ) and ( q = -1 ).
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